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01_3Sum.py
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76 lines (53 loc) · 1.99 KB
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# Question link - https://leetcode.com/problems/3sum/description/?envType=study-plan-v2&envId=top-interview-150
class Solution:
def threeSum(self, nums: List[int]) -> List[List[int]]:
ans = []
n = len(nums)
nums.sort()
for i in range(n):
if i>0 and nums[i] == nums[i-1]:
continue
j = i + 1
k = n - 1
while j < k :
sum_val = nums[i] + nums [j] + nums [k]
if sum_val < 0:
j += 1
elif sum_val > 0 :
k -= 1
else:
temp = [nums[i], nums[j], nums[k]]
ans.append(temp)
# Skip
j +=1
k -= 1
while j<k and nums[j] == nums[j-1]:
j+=1
while j<=k and nums[k] == nums[k+1]:
k-=1
return ans
# triplet_Set = set()
# n = len(nums)
# for i in range(n):
# hashset = set()
# for j in range(i+1 , n):
# third = - (nums[i] + nums[j])
# if third in hashset:
# temp = [nums[i] , nums[j] , third]
# temp.sort()
# triplet_Set.add(tuple(temp))
# hashset.add(nums[j])
# ans = [list(triplet) for triplet in triplet_Set]
# return ans
# triplet = set()
# n = len(nums)
# for i in range(n):
# for j in range(i+1,n):
# for k in range(j+1,n):
# if i != j and i != k and j != k:
# if nums[i] + nums[j] + nums[k] == 0:
# temp = [nums[i],nums[j],nums[k]]
# temp.sort()
# triplet.add(tuple(temp))
# ans = [list(trlet) for trlet in triplet]
# return ans