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‎src/1v1/96-Four-dimensional/2022F_TT2.md‎

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@@ -28,7 +28,188 @@ Your job is to write a simple booking app that asks the user to input a day of t
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In order to store the bookings, you should create a list of lists of booleans. That is to say, a list of seven elements where each element is a list of 24 boolean (True or False) values representing the booking status for a specific day/hour.
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::: tabs
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@tab 语法
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1. 列表的整数倍增加；
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```python
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lst = [1]
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print(lst * 20)
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```
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2. 字符串内置 strip()：去掉字符串的前后空格
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```python
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s = " sunday "
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new_s = s.strip()
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print(s)
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print(new_s)
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```
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3. 判断元素在不在序列当中
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```python
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In [1]: days_of_week = {
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...: "monday": 0,
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...: "tuesday": 1,
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...: "wednesday": 2,
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...: "thursday": 3,
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...: "friday": 4,
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...: "saturday": 5,
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...: "sunday": 6,
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...: }
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In [2]: 1 in days_of_week
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Out[2]: False
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In [3]: "monday" in days_of_week
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Out[3]: True
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In [4]: lst = [1, 2, 3, "aiyc"]
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In [5]: 1 in lst
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Out[5]: True
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In [6]: 300 not in lst
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Out[6]: True
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```
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4. 字符串转换问题
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```python
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s = "aiyuechuang"
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print(s.isdigit())
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s = "12112121212"
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print(s.isdigit())
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s = "12112121212 "
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print(s.isdigit())
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```
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@tab 逻辑详解
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注意⚠️：包含开始时间，无需取到 duration！
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1. 待一个小时的情况
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```python
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bookings = [[False] * 24, [False] * 24, [False] * 24, [False] * 24, [False] * 24, [False] * 24, [False] * 24]
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duration = 1
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start_time = 14
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week = 1
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print(bookings[week][14]) # 判断 14:00 本身是否空闲
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# print(bookings[week][14 + 1])
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```
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2. 待两个小时的情况
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```python
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bookings = [[False] * 24, [False] * 24, [False] * 24, [False] * 24, [False] * 24, [False] * 24, [False] * 24]
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duration = 2
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start = 14
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week = 1
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print(bookings[week][14]) # 判断 14:00 本身是否空闲
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print(bookings[week][14 + 1]) # 判断第一个小时是否空闲
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print(bookings[week][14 + 1 + 1]) # 判断第二个小时是否空闲
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```
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3. 待三个小时的情况
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```python
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bookings = [[False] * 24, [False] * 24, [False] * 24, [False] * 24, [False] * 24, [False] * 24, [False] * 24]
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duration = 3 # 待三个小时
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start = 14
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week = 1
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print(bookings[week][14])
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print(bookings[week][14 + 1]) # 判断第一个小时是否空闲
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print(bookings[week][14 + 1 + 1]) # 判断第二个小时是否空闲
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# print(bookings[week][14 + 1 + 1 + 1]) # 判断第三个小时是否空闲
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```
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4. Step 1：待三个小时以上的情况
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```python
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bookings = [[False] * 24, [False] * 24, [False] * 24, [False] * 24, [False] * 24, [False] * 24, [False] * 24]
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duration = 3 # 待三个小时
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start = 14
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week = 1
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# 判断三个小时 or 三个小时以上，我如下执行
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print(bookings[week][14])
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print(bookings[week][14 + 1]) # 判断第一个小时是否空闲
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print(bookings[week][14 + 2]) # 判断第二个小时是否空闲
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# print(bookings[week][14 + 3]) # 判断第三个小时是否空闲
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```
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5. Step 2：待三个小时以上的情况
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```python
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bookings = [[False] * 24, [False] * 24, [False] * 24, [False] * 24, [False] * 24, [False] * 24, [False] * 24]
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duration = 3 # 待三个小时
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start = 14
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week = 1
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# 判断三个小时 or 三个小时以上，我如下执行
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print(bookings[week][14])
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print(bookings[week][start_time + 1]) # 判断第一个小时是否空闲
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print(bookings[week][start_time + 2]) # 判断第二个小时是否空闲
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# print(bookings[week][start_time + 3]) # 判断第三个小时是否空闲
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```
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6. Step 3：待三个小时以上的情况
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```python
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bookings = [[False] * 24, [False] * 24, [False] * 24, [False] * 24, [False] * 24, [False] * 24, [False] * 24]
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duration = 3 # 待三个小时
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start = 14
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week = 1
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print(bookings[week][14 + 0]) # 可以制作一个 +0 （类似数学当中构造一个：规律 or 公式）类似数学几何画辅助线
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print(bookings[week][start_time + 1])
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print(bookings[week][start_time + 2])
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# print(bookings[week][start_time + 3])
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```
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7. Step 4：如何得到0～3？
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```python
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for i in range(3):
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print(i)
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# ---output---
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0
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1
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2
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```
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8. Step 5:
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```python
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bookings = [[False] * 24, [False] * 24, [False] * 24, [False] * 24, [False] * 24, [False] * 24, [False] * 24]
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duration = 3 # 待三个小时
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start = 14
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week = 1
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# 如何得到0～3？
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for i in range(3):
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print(bookings[week][start + i])
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```
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9. Step 6:
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```python
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bookings = [[False] * 24, [False] * 24, [False] * 24, [False] * 24, [False] * 24, [False] * 24, [False] * 24]
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duration = 3 # 待三个小时
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start = 14
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week = 1
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# 如何得到0～3？
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for i in range(duration):
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print(bookings[week][start + i])
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```
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:::
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