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ArrayandOperations.cpp
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184 lines (157 loc) · 3.13 KB
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#include <iostream>
#include <cmath>
#include <algorithm>
#define N 101010
#define ll long long
using namespace std;
int n, m;
ll arr[N], tree[N * 4][3], ad[N * 4], sq[N * 4]; // 0 -> sum, 1 -> max, 2 -> min
void input()
{
cin >> n >> m;
for (int i = 1; i <= n; i++) cin >> arr[i];
}
void update(int node)
{
tree[node][0] = tree[node * 2][0] + tree[node * 2 + 1][0];
tree[node][1] = max(tree[node * 2][1], tree[node * 2 + 1][1]);
tree[node][2] = min(tree[node * 2][2], tree[node * 2 + 1][2]);
}
void init(int s, int e, int node)
{
if (s == e)
{
tree[node][0] = arr[s];
tree[node][1] = arr[s];
tree[node][2] = arr[s];
return;
}
int m = (s + e) / 2;
init(s, m, node * 2);
init(m + 1, e, node * 2 + 1);
update(node);
}
void lazy_add(int s, int e, int node)
{
tree[node][0] += ad[node] * (e - s + 1);
tree[node][1] += ad[node];
tree[node][2] += ad[node];
if (s != e)
{
ad[node * 2] += ad[node];
ad[node * 2 + 1] += ad[node];
}
ad[node] = 0;
}
void lazy_sqr(int s, int e, int node)
{
tree[node][0] = (sq[node] + ad[node]) * (e - s + 1);
tree[node][1] = sq[node] + ad[node];
tree[node][2] = sq[node] + ad[node];
if (s != e)
{
sq[node * 2] = sq[node];
ad[node * 2] = ad[node];
sq[node * 2 + 1] = sq[node];
ad[node * 2 + 1] = ad[node];
}
sq[node] = 0;
ad[node] = 0;
}
void check(int s, int e, int node)
{
if (!ad[node] && !sq[node]) return;
/* add만 발생할 시 */
if (!sq[node]) lazy_add(s, e, node);
/* sqrt도 해야하는 경우 */
else lazy_sqr(s, e, node);
}
void add(int s, int e, int node, int l, int r, ll val)
{
check(s, e, node);
if (s > r || e < l) return;
if (s >= l && e <= r)
{
if (!sq[node])
{
ad[node] += val;
check(s, e, node);
return;
}
}
int m = (s + e) / 2;
add(s, m, node * 2, l, r, val);
add(m + 1, e, node * 2 + 1, l, r, val);
update(node);
}
void sqr(int s, int e, int node, int l, int r)
{
check(s, e, node);
if (s > r || e < l) return;
if (s >= l && e <= r)
{
int sqx = sqrt(tree[node][1]);
int sqn = sqrt(tree[node][2]);
if (sqx == sqn)
{
sq[node] = sqx;
check(s, e, node);
return;
}
if (tree[node][1] == tree[node][2] + 1)
{
ad[node] = sqn - tree[node][2];
check(s, e, node);
return;
}
}
int m = (s + e) / 2;
sqr(s, m, node * 2, l, r);
sqr(m + 1, e, node * 2 + 1, l, r);
update(node);
}
ll output(int s, int e, int node, int l, int r)
{
check(s, e, node);
if (s > r || e < l) return 0;
if (s >= l && e <= r) return tree[node][0];
int m = (s + e) / 2;
return output(s, m, node * 2, l, r) + output(m + 1, e, node * 2 + 1, l, r);
}
void solution()
{
init(1, n, 1);
while (m--)
{
int a, b, c;
ll d;
cin >> a;
if (a == 1)
{
cin >> b >> c >> d;
add(1, n, 1, b, c, d);
}
else if (a == 2)
{
cin >> b >> c;
sqr(1, n, 1, b, c);
}
else
{
cin >> b >> c;
cout << output(1, n, 1, b, c) << '\n';
}
}
}
void solve()
{
input();
solution();
}
int main(void)
{
ios_base::sync_with_stdio(false);
cin.tie(NULL);
solve();
return 0;
}