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[level 3] Title: 조건별로 분류하여 주문상태 출력하기, Time: 0.00 ms, Memory: 0.0 MB -BaekjoonHub
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‎프로그래머스/3/131113. 조건별로 분류하여 주문상태 출력하기/README.md‎

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# [level 3] 조건별로 분류하여 주문상태 출력하기 - 131113
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[문제 링크](https://school.programmers.co.kr/learn/courses/30/lessons/131113)
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### 성능 요약
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메모리: 0.0 MB, 시간: 0.00 ms
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### 구분
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코딩테스트 연습 > String， Date
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### 채점결과
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Empty
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### 제출 일자
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2025년 11월 10일 17:37:14
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### 문제 설명
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<p>다음은 식품공장의 주문정보를 담은 <code>FOOD_ORDER</code> 테이블입니다. <code>FOOD_ORDER</code> 테이블은 다음과 같으며 <code>ORDER_ID</code>, <code>PRODUCT_ID</code>, <code>AMOUNT</code>, <code>PRODUCE_DATE</code>, <code>IN_DATE</code>,<code>OUT_DATE</code>,<code>FACTORY_ID</code>, <code>WAREHOUSE_ID</code>는 각각 주문 ID, 제품 ID, 주문양, 생산일자, 입고일자, 출고일자, 공장 ID, 창고 ID를 의미합니다.</p>
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<table class="table">
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<thead><tr>
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<th>Column name</th>
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<th>Type</th>
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<th>Nullable</th>
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</tr>
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</thead>
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<tbody><tr>
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<td>ORDER_ID</td>
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<td>VARCHAR(10)</td>
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<td>FALSE</td>
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</tr>
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<tr>
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<td>PRODUCT_ID</td>
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<td>VARCHAR(5)</td>
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<td>FALSE</td>
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</tr>
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<tr>
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<td>AMOUNT</td>
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<td>NUMBER</td>
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<td>FALSE</td>
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</tr>
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<tr>
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<td>PRODUCE_DATE</td>
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<td>DATE</td>
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<td>TRUE</td>
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</tr>
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<tr>
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<td>IN_DATE</td>
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<td>DATE</td>
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<td>TRUE</td>
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</tr>
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<tr>
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<td>OUT_DATE</td>
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<td>DATE</td>
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<td>TRUE</td>
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</tr>
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<tr>
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<td>FACTORY_ID</td>
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<td>VARCHAR(10)</td>
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<td>FALSE</td>
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</tr>
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<tr>
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<td>WAREHOUSE_ID</td>
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<td>VARCHAR(10)</td>
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<td>FALSE</td>
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</tr>
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</tbody>
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</table>
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<hr>
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<h5>문제</h5>
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<p><code>FOOD_ORDER</code> 테이블에서 2022년 5월 1일을 기준으로 주문 ID, 제품 ID, 출고일자, 출고여부를 조회하는 SQL문을 작성해주세요. 출고여부는 2022년 5월 1일까지 출고완료로 이 후 날짜는 출고 대기로 미정이면 출고미정으로 출력해주시고, 결과는 주문 ID를 기준으로 오름차순 정렬해주세요.</p>
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<hr>
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<h5>예시</h5>
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<p><code>FOOD_ORDER</code> 테이블이 다음과 같을 때</p>
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<table class="table">
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<thead><tr>
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<th>ORDER_ID</th>
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<th>PRODUCT_ID</th>
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<th>AMOUNT</th>
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<th>PRODUCE_DATE</th>
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<th>IN_DATE</th>
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<th>OUT_DATE</th>
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<th>FACTORY_ID</th>
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<th>WAREHOUSE_ID</th>
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</tr>
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</thead>
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<tbody><tr>
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<td>OD00000051</td>
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<td>P0002</td>
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<td>4000</td>
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<td>2022-04-01</td>
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<td>2022-04-21</td>
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<td>2022-04-21</td>
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<td>FT19970003</td>
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<td>WH0005</td>
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</tr>
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<tr>
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<td>OD00000052</td>
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<td>P0003</td>
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<td>2500</td>
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<td>2022-04-10</td>
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<td>2022-04-27</td>
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<td>2022-04-27</td>
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<td>FT19970003</td>
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<td>WH0006</td>
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</tr>
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<tr>
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<td>OD00000053</td>
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<td>P0005</td>
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<td>6200</td>
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<td>2022-04-15</td>
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<td>2022-04-30</td>
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<td>2022-05-01</td>
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<td>FT19940003</td>
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<td>WH0003</td>
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</tr>
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<tr>
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<td>OD00000054</td>
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<td>P0006</td>
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<td>1000</td>
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<td>2022-04-21</td>
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<td>2022-04-30</td>
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<td>NULL</td>
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<td>FT19940003</td>
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<td>WH0009</td>
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</tr>
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<tr>
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<td>OD00000055</td>
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<td>P0008</td>
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<td>1500</td>
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<td>2022-04-25</td>
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<td>2022-05-11</td>
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<td>2022-05-11</td>
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<td>FT19980003</td>
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<td>WH0009</td>
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</tr>
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</tbody>
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</table>
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<p>SQL을 실행하면 다음과 같이 출력되어야 합니다.</p>
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<table class="table">
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<thead><tr>
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<th>ORDER_ID</th>
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<th>PRODUCT_ID</th>
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<th>OUT_DATE</th>
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<th>출고여부</th>
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</tr>
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</thead>
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<tbody><tr>
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<td>OD00000051</td>
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<td>P0002</td>
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<td>2022-04-21</td>
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<td>출고완료</td>
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</tr>
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<tr>
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<td>OD00000052</td>
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<td>P0003</td>
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<td>2022-04-27</td>
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<td>출고완료</td>
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</tr>
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<tr>
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<td>OD00000053</td>
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<td>P0005</td>
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<td>2022-05-01</td>
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<td>출고완료</td>
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</tr>
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<tr>
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<td>OD00000054</td>
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<td>P0006</td>
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<td></td>
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<td>출고미정</td>
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</tr>
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<tr>
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<td>OD00000055</td>
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<td>P0008</td>
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<td>2022-05-11</td>
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<td>출고대기</td>
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</tr>
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</tbody>
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</table>
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> 출처: 프로그래머스 코딩 테스트 연습, https://school.programmers.co.kr/learn/challenges

‎프로그래머스/3/131113. 조건별로 분류하여 주문상태 출력하기/조건별로 분류하여 주문상태 출력하기.sql‎

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-- 코드를 입력하세요
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SELECT
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ORDER_ID,
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PRODUCT_ID,
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DATE_FORMAT(OUT_DATE, '%Y-%m-%d') AS OUT_DATE,
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CASE
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WHEN OUT_DATE IS NULL THEN '출고미정'
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WHEN OUT_DATE <='2022-05-01' THEN '출고완료'
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ELSE '출고대기'
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END AS '출고여부'
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FROM FOOD_ORDER
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ORDER BY ORDER_ID;
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# SELECT order_id
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# , product_id
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# , TO_CHAR(out_date, 'YYYY-MM-DD') AS out_date
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# , CASE
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# WHEN out_date <= DATE '2022-05-01'THEN '출고완료'
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# WHEN out_date > DATE '2022-05-01' THEN '출고대기'
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# ELSE '출고미정'
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# END AS 출고여부
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# -- 기준일보다 작다면 출고완료, 크다면 출고대기, 그 외는 출고미정
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# FROM food_order
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# ORDER BY order_id ASC;

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