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[level 2] Title: 특정 물고기를 잡은 총 수 구하기, Time: , Memory: undefined -BaekjoonHub
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‎프로그래머스/2/298518. 특정 물고기를 잡은 총 수 구하기/README.md‎

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# [level 2] 특정 물고기를 잡은 총 수 구하기 - 298518
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[문제 링크](https://school.programmers.co.kr/learn/courses/30/lessons/298518)
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### 성능 요약
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메모리: undefined, 시간:
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### 구분
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코딩테스트 연습 > SELECT
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### 채점결과
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합계: 100.0 / 100.0
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### 제출 일자
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2025년 11월 03일 14:54:50
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### 문제 설명
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<p>낚시앱에서 사용하는 <code>FISH_INFO</code> 테이블은 잡은 물고기들의 정보를 담고 있습니다. <code>FISH_INFO</code> 테이블의 구조는 다음과 같으며 <code>ID</code>, <code>FISH_TYPE</code>, <code>LENGTH</code>, <code>TIME</code>은 각각 잡은 물고기의 ID, 물고기의 종류(숫자), 잡은 물고기의 길이(cm), 물고기를 잡은 날짜를 나타냅니다. </p>
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<table class="table">
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<thead><tr>
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<th>Column name</th>
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<th>Type</th>
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<th>Nullable</th>
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</tr>
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</thead>
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<tbody><tr>
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<td>ID</td>
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<td>INTEGER</td>
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<td>FALSE</td>
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</tr>
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<tr>
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<td>FISH_TYPE</td>
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<td>INTEGER</td>
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<td>FALSE</td>
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</tr>
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<tr>
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<td>LENGTH</td>
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<td>FLOAT</td>
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<td>TRUE</td>
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</tr>
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<tr>
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<td>TIME</td>
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<td>DATE</td>
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<td>FALSE</td>
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</tr>
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</tbody>
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</table>
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<p>단, 잡은 물고기의 길이가 10cm 이하일 경우에는 <code>LENGTH</code> 가 NULL 이며, <code>LENGTH</code> 에 NULL 만 있는 경우는 없습니다.</p>
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<p><code>FISH_NAME_INFO</code> 테이블은 물고기의 이름에 대한 정보를 담고 있습니다. <code>FISH_NAME_INFO</code> 테이블의 구조는 다음과 같으며, <code>FISH_TYPE</code>, <code>FISH_NAME</code> 은 각각 물고기의 종류(숫자), 물고기의 이름(문자) 입니다.</p>
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<table class="table">
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<thead><tr>
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<th>Column name</th>
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<th>Type</th>
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<th>Nullable</th>
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</tr>
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</thead>
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<tbody><tr>
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<td>FISH_TYPE</td>
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<td>INTEGER</td>
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<td>FALSE</td>
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</tr>
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<tr>
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<td>FISH_NAME</td>
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<td>VARCHAR</td>
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<td>FALSE</td>
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</tr>
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</tbody>
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</table>
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<hr>
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<h5>문제</h5>
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<p><code>FISH_INFO</code> 테이블에서 잡은 <code>BASS</code>와 <code>SNAPPER</code>의 수를 출력하는 SQL 문을 작성해주세요. </p>
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<p>컬럼명은 'FISH_COUNT`로 해주세요.</p>
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<hr>
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<h5>예시</h5>
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<p>예를 들어 <code>FISH_INFO</code> 테이블이 다음과 같고</p>
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<table class="table">
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<thead><tr>
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<th>ID</th>
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<th>FISH_TYPE</th>
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<th>LENGTH</th>
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<th>TIME</th>
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</tr>
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</thead>
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<tbody><tr>
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<td>0</td>
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<td>0</td>
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<td>30</td>
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<td>2021/12/04</td>
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</tr>
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<tr>
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<td>1</td>
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<td>0</td>
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<td>50</td>
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<td>2020/03/07</td>
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</tr>
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<tr>
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<td>2</td>
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<td>0</td>
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<td>40</td>
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<td>2020/03/07</td>
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</tr>
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<tr>
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<td>3</td>
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<td>1</td>
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<td>20</td>
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<td>2022/03/09</td>
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</tr>
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<tr>
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<td>4</td>
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<td>1</td>
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<td>NULL</td>
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<td>2022/04/08</td>
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</tr>
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<tr>
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<td>5</td>
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<td>2</td>
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<td>13</td>
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<td>2021/04/28</td>
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</tr>
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<tr>
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<td>6</td>
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<td>0</td>
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<td>60</td>
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<td>2021/07/27</td>
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</tr>
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<tr>
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<td>7</td>
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<td>0</td>
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<td>55</td>
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<td>2021/01/18</td>
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</tr>
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<tr>
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<td>8</td>
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<td>2</td>
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<td>73</td>
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<td>2020/01/28</td>
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</tr>
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<tr>
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<td>9</td>
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<td>2</td>
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<td>73</td>
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<td>2021/04/08</td>
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</tr>
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<tr>
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<td>10</td>
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<td>2</td>
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<td>22</td>
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<td>2020/06/28</td>
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</tr>
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<tr>
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<td>11</td>
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<td>2</td>
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<td>17</td>
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<td>2022/12/23</td>
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</tr>
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</tbody>
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</table>
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<p><code>FISH_NAME_INFO</code> 테이블이 다음과 같다면</p>
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<table class="table">
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<thead><tr>
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<th>FISH_TYPE</th>
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<th>FISH_NAME</th>
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</tr>
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</thead>
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<tbody><tr>
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<td>0</td>
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<td>BASS</td>
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</tr>
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<tr>
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<td>1</td>
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<td>SNAPPER</td>
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</tr>
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<tr>
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<td>2</td>
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<td>ANCHOVY</td>
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</tr>
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</tbody>
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</table>
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<p>'BASS' 는 물고기 종류 0에 해당하고, 'SNAPPER' 는 물고기 종류 1에 해당하므로 잡은 'BASS' 와 'SNAPPER' 수는 7마리입니다.</p>
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<table class="table">
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<thead><tr>
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<th>FISH_COUNT</th>
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</tr>
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</thead>
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<tbody><tr>
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<td>7</td>
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</tr>
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</tbody>
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</table>
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> 출처: 프로그래머스 코딩 테스트 연습, https://school.programmers.co.kr/learn/challenges

‎프로그래머스/2/298518. 특정 물고기를 잡은 총 수 구하기/특정 물고기를 잡은 총 수 구하기.sql‎

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select count(*) as fish_count
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from fish_info as info
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join fish_name_info as name
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on info.fish_type = name.fish_type
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where name.fish_name = 'BASS' OR name.fish_name = 'SNAPPER';

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