Update getLastDigit function to use input parameter instead of constant value

Author: HoussamLh

Sprint-2/2-mandatory-debug/2.js

@@ -2,7 +2,11 @@
 
 // Predict the output of the following code:
 // =============> Write your prediction here
+// I predict that all three log statements will output: "The last digit of 42 is 3", "105 is 3", "806 is 3"
+// Because the getLastDigit function doesn’t use the input — it always returns the last digit of the constant 
+// `num = 103`.
 
+// Original Code
 const num = 103;
 
 function getLastDigit() {
@@ -15,10 +19,25 @@ console.log(`The last digit of 806 is ${getLastDigit(806)}`);
 
 // Now run the code and compare the output to your prediction
 // =============> write the output here
+// The actual output is:
+// The last digit of 42 is 3
+// The last digit of 105 is 3
+// The last digit of 806 is 3
+
 // Explain why the output is the way it is
 // =============> write your explanation here
+// The function `getLastDigit` doesn't take any parameter, and it always uses the fixed variable `num = 103`.
+// So regardless of the input in the log statements, the function always returns the last digit of 103, which is "3".
+
 // Finally, correct the code to fix the problem
 // =============> write your new code here
+function getLastDigit(number) {
+  return number.toString().slice(-1);
+}
+
+console.log(`The last digit of 42 is ${getLastDigit(42)}`);    // 2
+console.log(`The last digit of 105 is ${getLastDigit(105)}`);  // 5
+console.log(`The last digit of 806 is ${getLastDigit(806)}`);  // 6
+
+// Now the function works correctly by taking a number as input and returning its last digit.
 
-// This program should tell the user the last digit of each number.
-// Explain why getLastDigit is not working properly - correct the problem