Merge branch 'master' of https://github.com/DSLsofMath/BScProj2018

Author: AiStudent

Physics/src/Examples/Teeter.lhs

@@ -32,11 +32,8 @@ A torque (sv. vridmoment) is defined as:
 
 $$ \tau = distance\ from\ turning\ point \cdot force $$
 
-(soon not to be) Since all force values will be composited of a mass and the gravitation, we can ignore the gravitation.
-
 $$ \tau = distance\ from\ turning\ point \cdot mass \cdot gravitation $$
 
-
 > m1_torq = m1 *# (g *# beam_left_L)
 
 To get the beams torque on one side, we need to divide by 2 because the beam's torque is spread out linearly (the density of the beam is equal everywhere), which means the left parts mass centre is $half\ the\ distance$ of the left parts total length.
@@ -53,7 +50,7 @@ $$ beamL_{M} = \frac{beam\ left\ length}{beam\ length} \cdot beam_M $$
 
 We make an expression for $m2_{\tau}$, which involves our unknown distance x.
 
-$$ m2_{\tau} = m2 \cdot x $$
+$$ m2_{\tau} = m2 \cdot gravitation \cdot x $$
 
 For the teeter to be in balance, both sides torques should be equal.