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subtree of another tree solution
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/**
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* Definition for a binary tree node.
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* class TreeNode {
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* val: number
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* left: TreeNode | null
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* right: TreeNode | null
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* constructor(val?: number, left?: TreeNode | null, right?: TreeNode | null) {
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* this.val = (val===undefined ? 0 : val)
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* this.left = (left===undefined ? null : left)
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* this.right = (right===undefined ? null : right)
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* }
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* }
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*/
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function isSubtree(root: TreeNode | null, subRoot: TreeNode | null): boolean {
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if (!root) return false;
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const isSameTree = (root: TreeNode | null, subRoot: TreeNode | null): boolean => {
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if (!root && !subRoot) return true;
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if (!root || !subRoot) return false;
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if (root.val !== subRoot.val) return false;
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return isSameTree(root.left, subRoot.left) && isSameTree(root.right, subRoot.right);
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};
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const current = isSameTree(root, subRoot);
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const left = isSubtree(root.left, subRoot);
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const right = isSubtree(root.right, subRoot);
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return current || left || right;
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}

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