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top-k-frequent-elements solution
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/**
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* @param {number[]} nums
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* @param {number} k
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* @return {number[]}
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*/
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var topKFrequent = function (nums, k) {
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let result = [];
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const obj = nums.reduce((acc, cur) => {
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acc[cur] = (acc[cur] || 0) + 1;
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return acc;
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}, {});
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const frequentValues = Object.values(obj)
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.sort((a, b) => b - a)
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.slice(0, k);
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for (const [key, value] of Object.entries(obj)) {
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if (frequentValues.includes(value)) {
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result.push(parseInt(key));
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}
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}
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return result;
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};

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