feat: Solve design-add-and-search-words-data-structure problem

Author: hu6r1s

design-add-and-search-words-data-structure/hu6r1s,py

@@ -0,0 +1,35 @@
+class WordDictionary:
+    """
+    알고달레의 영상을 보고 했는데 아직 이해가 잘 되지 않음.
+    추가적인 학습 필요
+    """
+    def __init__(self):
+        self.root = {"$": True}
+
+    def addWord(self, word: str) -> None:
+        node = self.root
+        for ch in word:
+            if ch not in node:
+                node[ch] = {"$": False}
+            node = node[ch]
+        node["$"] = True
+
+    def search(self, word: str) -> bool:
+        def dfs(node, idx):
+            if idx == len(word):
+                return node["$"]
+            ch = word[idx]
+            if ch in node:
+                return dfs(node[ch], idx + 1)
+            if ch == ".":
+                if any(dfs(node[k], idx + 1) for k in node if k != "$"):
+                    return True
+            return False
+
+        return dfs(self.root, 0)
+
+
+# Your WordDictionary object will be instantiated and called as such:
+# obj = WordDictionary()
+# obj.addWord(word)
+# param_2 = obj.search(word)