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1 parent 19785ec commit 31620b5Copy full SHA for 31620b5
maximum-product-subarray/kayden.py
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+# 시간복잡도: O(N)
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+# 공간복잡도: O(1)
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+class Solution:
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+ def maxProduct(self, nums: List[int]) -> int:
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+ n = len(nums)
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+ positive, negative = 0, 0
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+
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+ if nums[0] > 0:
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+ positive = nums[0]
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+ else:
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+ negative = nums[0]
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+ answer = max(nums)
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+ for i in range(1, n):
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+ if nums[i] >= 0:
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+ positive *= nums[i]
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+ negative *= nums[i]
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+ if positive == 0:
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+ positive = nums[i]
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+ temp = positive
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+ positive = negative * nums[i]
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+ negative = temp * nums[i]
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+ if negative == 0:
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+ negative = nums[i]
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+ answer = max(answer, positive)
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+ return answer
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