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mykoo
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GUMUNYEONG.js : top-k-frequent-elements solution
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/**
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* @param {number[]} nums
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* @param {number} k
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* @return {number[]}
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*/
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var topKFrequent = function (nums, k) {
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let result = [];
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let fObj = {};
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for (let i = 0; i < nums.length; i++) {
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const n = nums[i];
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fObj[n] ? fObj[n]++ : fObj[n] = 1;
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}
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Object
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.entries(fObj)
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.sort((a, b) => b[1] - a[1])
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.slice(0, k)
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.filter(v => result.push(v[0]));
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return result;
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};

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