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feat: missing number
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missing-number/anniemon.js

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/**
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* 시간 복잡도: nums.length + 1만큼 순회하므로 O(n)
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* 공간 복잡도: totalSum, numsSum 변수를 사용하므로 O(1)
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*/
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/**
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* @param {number[]} nums
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* @return {number}
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*/
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var missingNumber = function(nums) {
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let totalSum = 0;
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for(let i = 0; i <= nums.length; i++) {
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totalSum += i;
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}
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let numsSum = 0;
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for(const n of nums) {
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numsSum += n;
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}
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return totalSum - numsSum;
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};

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