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Feat: valid-palindrome Solution
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valid-palindrome/oddong.py

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import re
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class Solution:
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def isPalindrome(self, s: str) -> bool:
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filtered_phrase = re.sub("[^a-zA-Z0-9]", "", s).lower()
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if filtered_phrase == filtered_phrase[::-1]:
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return True
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else:
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return False

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