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Time: 2 ms (19.04%), Space: 16 MB (14.06%) - LeetHub
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# Definition for singly-linked list.
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# class ListNode(object):
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# def __init__(self, val=0, next=None):
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# self.val = val
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# self.next = next
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class Solution(object):
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def reverseList(self, head):
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"""
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:type head: Optional[ListNode]
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:rtype: Optional[ListNode]
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"""
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temp =[]
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while head:
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temp.append(head.val)
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head = head.next
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temp = temp[::-1] #Reverse the temp list
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myNode = ListNode() #Create the Listnode instance
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current = myNode
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for value in temp:
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current.next = ListNode(value)
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current = current.next
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return myNode.next

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