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| 1 | +/** |
| 2 | + * [Problem]: [178] Graph Valid Tree |
| 3 | + * (https://www.lintcode.com/problem/178/) |
| 4 | + */ |
| 5 | + |
| 6 | +export class Solution { |
| 7 | + /** |
| 8 | + * @param n: An integer |
| 9 | + * @param edges: a list of undirected edges |
| 10 | + * @return: true if it's a valid tree, or false |
| 11 | + */ |
| 12 | + //시간복잡도 O(n+e) |
| 13 | + //공간복잡도 O(n+e) |
| 14 | + validTree(n: number, edges: number[][]): boolean { |
| 15 | + const graph: number[][] = Array.from({ length: n }, () => []); |
| 16 | + for (const [a, b] of edges) { |
| 17 | + graph[a].push(b); |
| 18 | + graph[b].push(a); |
| 19 | + } |
| 20 | + |
| 21 | + const visited = new Set<number>(); |
| 22 | + |
| 23 | + function hasCycle(node: number, prev: number): boolean { |
| 24 | + if (visited.has(node)) return true; |
| 25 | + visited.add(node); |
| 26 | + |
| 27 | + for (const neighbor of graph[node]) { |
| 28 | + if (neighbor === prev) continue; |
| 29 | + if (hasCycle(neighbor, node)) return true; |
| 30 | + } |
| 31 | + return false; |
| 32 | + } |
| 33 | + |
| 34 | + if (hasCycle(0, -1)) return false; |
| 35 | + |
| 36 | + return visited.size === n; |
| 37 | + } |
| 38 | + |
| 39 | + //시간복잡도 O(n) |
| 40 | + //공간복잡도 O(n) |
| 41 | + validTree2(n: number, edges: number[][]): boolean { |
| 42 | + if (edges.length !== n - 1) return false; |
| 43 | + |
| 44 | + const graph: number[][] = Array.from({ length: n }, () => []); |
| 45 | + for (const [a, b] of edges) { |
| 46 | + graph[a].push(b); |
| 47 | + graph[b].push(a); |
| 48 | + } |
| 49 | + |
| 50 | + const visited = new Set<number>(); |
| 51 | + |
| 52 | + function dfs(node: number) { |
| 53 | + visited.add(node); |
| 54 | + for (const neighbor of graph[node]) { |
| 55 | + if (!visited.has(neighbor)) { |
| 56 | + dfs(neighbor); |
| 57 | + } |
| 58 | + } |
| 59 | + } |
| 60 | + |
| 61 | + dfs(0); |
| 62 | + |
| 63 | + return visited.size === n; |
| 64 | + } |
| 65 | +} |
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