|
| 1 | +/** |
| 2 | + Tries + BFS를 활용한 방식 |
| 3 | + addWord() |
| 4 | + 문자열 word의 길이 -> N |
| 5 | + 시간 복잡도 : O(N) |
| 6 | + 공간 복잡도 : O(N) |
| 7 | + search() |
| 8 | + Tries 내부의 노드 개수 -> M |
| 9 | + 시간 복잡도 : O(M) |
| 10 | + 공간 복잡도 : O(M) |
| 11 | +*/ |
| 12 | +class WordDictionary { |
| 13 | + public Map<Character, WordNode> wordMap; |
| 14 | + |
| 15 | + public WordDictionary() { |
| 16 | + wordMap = new HashMap<>(); |
| 17 | + } |
| 18 | + |
| 19 | + public void addWord(String word) { |
| 20 | + WordNode wordNode = null; |
| 21 | + char ch = word.charAt(0); |
| 22 | + wordNode = wordMap.get(ch); |
| 23 | + |
| 24 | + if(wordNode == null) { |
| 25 | + boolean isFirstWord = word.length() == 1; |
| 26 | + wordNode = new WordNode(ch, isFirstWord); |
| 27 | + wordMap.put(ch, wordNode); |
| 28 | + } |
| 29 | + |
| 30 | + for(int idx = 1; idx < word.length(); idx++) { |
| 31 | + char target = word.charAt(idx); |
| 32 | + boolean isLeaf = word.length() - 1 == idx; |
| 33 | + wordNode = wordNode.next.computeIfAbsent(target, key -> new WordNode(key, isLeaf)); |
| 34 | + } |
| 35 | + wordNode.isLeaf = true; |
| 36 | + |
| 37 | + |
| 38 | + } |
| 39 | + |
| 40 | + public boolean search(String word) { |
| 41 | + Queue<Node> que = new ArrayDeque<>(); |
| 42 | + boolean result = false; |
| 43 | + char ch = word.charAt(0); |
| 44 | + WordNode wordNode = wordMap.get(ch); |
| 45 | + int len = word.length(); |
| 46 | + |
| 47 | + if(ch == '.' && wordMap.size() != 0) { |
| 48 | + for(Map.Entry<Character, WordNode> entry : wordMap.entrySet()) { |
| 49 | + que.add(new Node(entry.getValue(), 1)); |
| 50 | + } |
| 51 | + } |
| 52 | + |
| 53 | + if (wordNode != null) { |
| 54 | + que.add(new Node(wordNode, 1)); |
| 55 | + } |
| 56 | + |
| 57 | + |
| 58 | + |
| 59 | + while(!que.isEmpty()) { |
| 60 | + Node node = que.poll(); |
| 61 | + if(node.idx == len && node.wordNode.isLeaf) { |
| 62 | + result = true; |
| 63 | + break; |
| 64 | + } |
| 65 | + |
| 66 | + if(node.idx == len) { |
| 67 | + continue; |
| 68 | + } |
| 69 | + |
| 70 | + char target = word.charAt(node.idx); |
| 71 | + |
| 72 | + if(target == '.' && node.wordNode.next.size() != 0) { |
| 73 | + for(Map.Entry<Character, WordNode> entry : node.wordNode.next.entrySet()) { |
| 74 | + que.add(new Node(entry.getValue(), node.idx + 1)); |
| 75 | + } |
| 76 | + continue; |
| 77 | + } |
| 78 | + |
| 79 | + |
| 80 | + if (!node.wordNode.next.containsKey(target)) { |
| 81 | + continue; |
| 82 | + } |
| 83 | + |
| 84 | + que.add(new Node(node.wordNode.next.get(target), node.idx + 1)); |
| 85 | + } |
| 86 | + |
| 87 | + return result; |
| 88 | + |
| 89 | + } |
| 90 | +} |
| 91 | + |
| 92 | +class Node { |
| 93 | + WordNode wordNode; |
| 94 | + int idx; |
| 95 | + public Node(WordNode wordNode, int idx) { |
| 96 | + this.wordNode = wordNode; |
| 97 | + this.idx = idx; |
| 98 | + } |
| 99 | +} |
| 100 | + |
| 101 | +class WordNode { |
| 102 | + char ch; |
| 103 | + Map<Character, WordNode> next; |
| 104 | + boolean isLeaf; |
| 105 | + |
| 106 | + public WordNode(char ch) { |
| 107 | + this(ch, false); |
| 108 | + } |
| 109 | + |
| 110 | + public WordNode(char ch, boolean isLeaf) { |
| 111 | + next = new HashMap<>(); |
| 112 | + this.ch = ch; |
| 113 | + this.isLeaf = isLeaf; |
| 114 | + } |
| 115 | + |
| 116 | +} |
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