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non-overlapping intervals solution
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function eraseOverlapIntervals(intervals: number[][]): number {
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intervals.sort((a, b) => a[1] - b[1]);
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let removedCount = 0;
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let prevEnd = intervals[0][1];
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for (let i = 1; i < intervals.length; i++) {
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const [start, end] = intervals[i];
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if (prevEnd > start) {
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removedCount++;
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} else {
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prevEnd = end;
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}
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}
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return removedCount;
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}

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