|
| 1 | +// Approach 3 |
| 2 | +// ⏳ Time Complexity: O(n) ✅ |
| 3 | +// 💾 Space Complexity: O(n) |
| 4 | + |
| 5 | +function longestConsecutive(nums: number[]): number { |
| 6 | + if (nums.length === 0) return 0; |
| 7 | + |
| 8 | + const numSet = new Set<number>(nums); |
| 9 | + // The Set stores O(n) numbers. |
| 10 | + let longest = 0; |
| 11 | + |
| 12 | + for (const num of numSet) { |
| 13 | + if (!numSet.has(num - 1)) { |
| 14 | + // Set.has() operation runs in O(1) average time. |
| 15 | + let size = 1; |
| 16 | + |
| 17 | + while (numSet.has(num + size)) { |
| 18 | + size += 1; |
| 19 | + } |
| 20 | + |
| 21 | + longest = Math.max(longest, size); |
| 22 | + } |
| 23 | + } |
| 24 | + |
| 25 | + return longest; |
| 26 | +} |
| 27 | + |
| 28 | + |
| 29 | +// Approach 2 |
| 30 | +// ⏳ Time Complexity: O(n * log n) |
| 31 | +// 💾 Space Complexity: O(1) |
| 32 | + |
| 33 | +// function longestConsecutive(nums: number[]): number { |
| 34 | +// if (nums.length === 0) { |
| 35 | +// return 0; |
| 36 | +// } |
| 37 | + |
| 38 | +// nums.sort((a, b) => a - b); |
| 39 | +// // Sorting takes O(n * log n) time. |
| 40 | +// // Sorting is in-place -> O(1) extra space |
| 41 | + |
| 42 | +// let longest = 0; |
| 43 | + |
| 44 | +// let size = 1; |
| 45 | + |
| 46 | +// for (let i = 0; i < nums.length - 1; i++) { |
| 47 | +// if (nums[i] === nums[i + 1]) { |
| 48 | +// continue; |
| 49 | +// } |
| 50 | + |
| 51 | +// if (nums[i] + 1 === nums[i + 1]) { |
| 52 | +// size += 1; |
| 53 | +// } else { |
| 54 | +// longest = Math.max(longest, size); |
| 55 | +// size = 1; |
| 56 | +// } |
| 57 | +// } |
| 58 | + |
| 59 | +// longest = Math.max(longest, size); |
| 60 | + |
| 61 | +// return longest; |
| 62 | +// } |
| 63 | + |
| 64 | + |
| 65 | +// Approach 1 |
| 66 | +// ❌ Time Limit Exceeded! |
| 67 | +// ⏳ Time Complexity: O(n^3) |
| 68 | +// 💾 Space Complexity: O(1) |
| 69 | + |
| 70 | +// function longestConsecutive(nums: number[]): number { |
| 71 | +// let longest = 0; |
| 72 | + |
| 73 | +// for (const num of nums) { |
| 74 | +// let size = 1; |
| 75 | +// while (nums.includes(num + size)) { |
| 76 | +// size += 1; |
| 77 | +// } |
| 78 | + |
| 79 | +// longest = Math.max(longest, size); |
| 80 | +// } |
| 81 | + |
| 82 | +// return longest; |
| 83 | +// } |
| 84 | + |
| 85 | + |
0 commit comments