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feat: Solve validate-binary-search-tree problem
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# Definition for a binary tree node.
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# class TreeNode:
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# def __init__(self, val=0, left=None, right=None):
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# self.val = val
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# self.left = left
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# self.right = right
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class Solution:
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"""
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TC: O(n)
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SC: 최악의 경우 -> O(n), 평균 -> O(log n)
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- 트리가 균일할 경우 평균의 복잡도가 나오고
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- 한쪽이 치우친 경우 최악의 경우로 나온다.
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"""
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def isValidBST(self, root: Optional[TreeNode]) -> bool:
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def validate(node, left, right):
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if not node:
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return True
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if not (left < node.val < right):
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return False
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return validate(node.left, left, node.val) and validate(node.right, node.val, right)
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return validate(root, float("-inf"), float("inf"))

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