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solve(w04): 153. Find Minimum in Rotated Sorted Array
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# https://leetcode.com/problems/find-minimum-in-rotated-sorted-array/
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from typing import List
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class Solution:
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def findMin(self, nums: List[int]) -> int:
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"""
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[Complexity]
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- TC: O(logn)
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- SC: O(1)
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[Approach]
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기본적으로 rotated sorted array에서 O(logn) time에 minimum element를 찾아야하므로
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binary search를 사용한다. 규칙을 찾아보면 다음과 같다.
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- nums[mid] > nums[hi]: min element가 오른쪽 영역인 (mid, hi]에 있음
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- nums[mid] < nums[hi]: min element가 왼쪽 영역인 [lo, mid]에 있음
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"""
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lo, hi = 0, len(nums) - 1
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while lo < hi:
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mid = lo + (hi - lo) // 2
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if nums[mid] > nums[hi]:
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lo = mid + 1 # (mid, hi]에 min element 존재
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else:
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hi = mid # [lo, mid]에 min element 존재
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return nums[lo]

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