top k frequent elements solution

Author: ayleeee

top-k-frequent-elements/ayleeee.py

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+class Solution:
+    def topKFrequent(self, nums: List[int], k: int) -> List[int]:
+        dict_map = {}
+        for a in nums:
+            if a in dict_map:
+                dict_map[a] += 1
+            else:
+                dict_map[a] = 1
+        lst = sorted(dict_map.items(), key=lambda x: x[1], reverse=True)  # 공백 수정
+        return [item[0] for item in lst[0:k]]