|
| 1 | +''' |
| 2 | +Time complexity : O(n ^ (target / min_val)) |
| 3 | +Space complexity : O(target / min_val) |
| 4 | +backtracking |
| 5 | +c = [2], total = 2 |
| 6 | +c = [2, 2], total = 4 |
| 7 | +c = [2, 2, 2] total = 6 |
| 8 | +c = [2, 2, 2, 2] total = 8, 초과 backtrack |
| 9 | +c = [2, 2, 2, 3] total = 9, 초과 backtrack |
| 10 | +c = [2, 2, 2, 6] total = 12, 초과 backtrack |
| 11 | +c = [2, 2, 2, 7] total = 13, 초과 backtrack |
| 12 | +c = [2, 2, 3] total = 7 정답 추가 |
| 13 | +c = [2, 2, 6] total = 10, 초과 backtrack |
| 14 | +c = [2, 2, 7] total = 11, 초과 backtrack |
| 15 | +.... |
| 16 | +[2,2,3], [7] |
| 17 | +
|
| 18 | +''' |
| 19 | + |
| 20 | +class Solution: |
| 21 | + def combinationSum(self, candidates: List[int], target: int) -> List[List[int]]: |
| 22 | + result = [] |
| 23 | + |
| 24 | + def backtrack(start, current, total): |
| 25 | + if total == target: |
| 26 | + result.append(list(current)) |
| 27 | + return |
| 28 | + if total > target: |
| 29 | + return |
| 30 | + |
| 31 | + for i in range(start, len(candidates)): |
| 32 | + current.append(candidates[i]) |
| 33 | + backtrack(i, current, total + candidates[i]) |
| 34 | + current.pop() |
| 35 | + backtrack(0, [], 0) |
| 36 | + return result |
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