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longest-common-subsequence
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/**
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* @param {number[]} nums
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* @return {number}
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*/
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var longestConsecutive = function (nums) {
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const set = new Set();
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// set 생성 : O(n)
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for (const num of nums) {
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set.add(num);
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}
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let res = 0;
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// set 순회 : O(n)
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for (const num of set) {
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if (set.has(num - 1)) continue;
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let tmp = 1;
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let cur = num;
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// While 루프 전체: O(n)
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while (true) {
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const v = (cur += 1);
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if (set.has(v)) tmp += 1;
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else break;
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}
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if (tmp > res) res = tmp;
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}
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return res;
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};

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