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1 parent bba4367 commit fbffd5eCopy full SHA for fbffd5e
longest-substring-without-repeating-characters/yyyyyyyyyKim.py
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+class Solution:
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+ def lengthOfLongestSubstring(self, s: str) -> int:
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+
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+ # 브루트포스(시간복잡도 : O(n^2))
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+ answer = 0
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+ for i in range(len(s)):
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+ # 중복없는 문자열을 저장할 집합
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+ substring = set()
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+ for j in range(i,len(s)):
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+ # 중복 문자를 만나면 break
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+ if s[j] in substring:
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+ break
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+ # 중복 아니면 문자 추가하고 긴 문자열 길이 비교해서 업데이트
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+ substring.add(s[j])
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+ answer = max(answer, len(substring))
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+ return answer
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