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all-nodes-distance-k-in-binary-tree.py
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41 lines (35 loc) · 1.17 KB
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# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Solution:
def distanceK(self, root: TreeNode, target: TreeNode, k: int) -> List[int]:
graph = defaultdict(list)
def build_graph(cur, parent):
if cur and parent:
graph[cur.val].append(parent.val)
graph[parent.val].append(cur.val)
if cur.left:
build_graph(cur.left, cur)
if cur.right:
build_graph(cur.right, cur)
build_graph(root, None)
queue = deque()
queue.append(target.val)
travelled = 0
visited = set()
while queue:
newQueue = deque()
if travelled == k:
return list(queue)
while queue:
node = queue.popleft()
visited.add(node)
for nodes in graph[node]:
if nodes not in visited:
newQueue.append(nodes)
travelled+=1
queue = newQueue
return []