adding samples, test, lints

Author: Guiners

genai/thinking/thinking-includethoughts-with-txt.js

@@ -52,6 +52,7 @@ async function generateContent(
       console.log(part.text);
     }
   }
+
   // Example Response:
   // **My Thought Process for Solving the Quadratic Equation**
   //
@@ -87,6 +88,7 @@ async function generateContent(
   // equation: (-2)² + 4(-2) + 4 = 0. That's 4 - 8 + 4 = 0. It checks out.
   //
   // Conclusion: the solution is x = -2. Confirmed.
+
   return response.text;
 }
 // [END googlegenaisdk_thinking_includethoughts_with_txt]

genai/thinking/thinking-with-txt.js

@@ -37,58 +37,59 @@ async function generateContent(
 
   console.log(response.text);
 
+  // Example Response:
+  //     Okay, let's solve the quadratic equation x² + 4x + 4 = 0.
+  //
+  //     We can solve this equation by factoring, using the quadratic formula,
+  //     or by recognizing it as a perfect square trinomial.
+  //
+  //     **Method 1: Factoring**
+  //
+  //     1.  We need two numbers that multiply to the constant term (4)
+  //         and add up to the coefficient of the x term (4).
+  //     2.  The numbers 2 and 2 satisfy these conditions: 2 * 2 = 4 and 2 + 2 = 4.
+  //     3.  So, we can factor the quadratic as:
+  //             (x + 2)(x + 2) = 0
+  //             or
+  //             (x + 2)² = 0
+  //     4.  For the product to be zero, the factor must be zero:
+  //             x + 2 = 0
+  //     5.  Solve for x:
+  //             x = -2
+  //
+  //     **Method 2: Quadratic Formula**
+  //
+  //     The quadratic formula for an equation ax² + bx + c = 0 is:
+  //         x = [-b ± sqrt(b² - 4ac)] / (2a)
+  //
+  //     1.  In our equation x² + 4x + 4 = 0, we have a = 1, b = 4, and c = 4.
+  //     2.  Substitute these values into the formula:
+  //             x = [-4 ± sqrt(4² - 4 * 1 * 4)] / (2 * 1)
+  //             x = [-4 ± sqrt(16 - 16)] / 2
+  //             x = [-4 ± sqrt(0)] / 2
+  //             x = [-4 ± 0] / 2
+  //             x = -4 / 2
+  //             x = -2
+  //
+  //     **Method 3: Perfect Square Trinomial**
+  //
+  //     1.  Notice that the expression x² + 4x + 4 fits the pattern of a perfect square trinomial:
+  //         a² + 2ab + b², where a = x and b = 2.
+  //     2.  We can rewrite the equation as:
+  //             (x + 2)² = 0
+  //     3.  Take the square root of both sides:
+  //             x + 2 = 0
+  //     4.  Solve for x:
+  //             x = -2
+  //
+  //     All methods lead to the same solution.
+  //
+  //     **Answer:**
+  //     The solution to the equation x² + 4x + 4 = 0 is x = -2.
+  //     This is a repeated root (or a root with multiplicity 2).
+
   return response.text;
 }
-// Example Response:
-//     Okay, let's solve the quadratic equation x² + 4x + 4 = 0.
-//
-//     We can solve this equation by factoring, using the quadratic formula,
-//     or by recognizing it as a perfect square trinomial.
-//
-//     **Method 1: Factoring**
-//
-//     1.  We need two numbers that multiply to the constant term (4)
-//         and add up to the coefficient of the x term (4).
-//     2.  The numbers 2 and 2 satisfy these conditions: 2 * 2 = 4 and 2 + 2 = 4.
-//     3.  So, we can factor the quadratic as:
-//             (x + 2)(x + 2) = 0
-//             or
-//             (x + 2)² = 0
-//     4.  For the product to be zero, the factor must be zero:
-//             x + 2 = 0
-//     5.  Solve for x:
-//             x = -2
-//
-//     **Method 2: Quadratic Formula**
-//
-//     The quadratic formula for an equation ax² + bx + c = 0 is:
-//         x = [-b ± sqrt(b² - 4ac)] / (2a)
-//
-//     1.  In our equation x² + 4x + 4 = 0, we have a = 1, b = 4, and c = 4.
-//     2.  Substitute these values into the formula:
-//             x = [-4 ± sqrt(4² - 4 * 1 * 4)] / (2 * 1)
-//             x = [-4 ± sqrt(16 - 16)] / 2
-//             x = [-4 ± sqrt(0)] / 2
-//             x = [-4 ± 0] / 2
-//             x = -4 / 2
-//             x = -2
-//
-//     **Method 3: Perfect Square Trinomial**
-//
-//     1.  Notice that the expression x² + 4x + 4 fits the pattern of a perfect square trinomial:
-//         a² + 2ab + b², where a = x and b = 2.
-//     2.  We can rewrite the equation as:
-//             (x + 2)² = 0
-//     3.  Take the square root of both sides:
-//             x + 2 = 0
-//     4.  Solve for x:
-//             x = -2
-//
-//     All methods lead to the same solution.
-//
-//     **Answer:**
-//     The solution to the equation x² + 4x + 4 = 0 is x = -2.
-//     This is a repeated root (or a root with multiplicity 2).
 
 // [END googlegenaisdk_thinking_with_txt]