@@ -19,52 +19,56 @@ def generate_content() -> str:
1919
2020 client = genai .Client ()
2121 response = client .models .generate_content (
22- model = "gemini-2.5-pro-exp -03-25" ,
22+ model = "gemini-2.5-pro-preview -03-25" ,
2323 contents = "solve x^2 + 4x + 4 = 0" ,
2424 )
2525 print (response .text )
2626 # Example Response:
2727 # Okay, let's solve the quadratic equation x² + 4x + 4 = 0.
2828 #
29- # There are a few ways to solve this:
29+ # We can solve this equation by factoring, using the quadratic formula, or by recognizing it as a perfect square trinomial.
3030 #
3131 # **Method 1: Factoring**
3232 #
33- # 1. **Look for two numbers** that multiply to the constant term (4) and add up to the coefficient of the x term (4).
34- # * The numbers are 2 and 2 (since 2 * 2 = 4 and 2 + 2 = 4) .
35- # 2 . **Factor the quadratic** using these numbers :
33+ # 1. We need two numbers that multiply to the constant term (4) and add up to the coefficient of the x term (4).
34+ # 2. The numbers 2 and 2 satisfy these conditions: 2 * 2 = 4 and 2 + 2 = 4.
35+ # 3 . So, we can factor the quadratic as :
3636 # (x + 2)(x + 2) = 0
37- # This can also be written as:
37+ # or
3838 # (x + 2)² = 0
39- # 3 . **Set the factor equal to zero** and solve for x :
39+ # 4 . For the product to be zero, the factor must be zero :
4040 # x + 2 = 0
41+ # 5. Solve for x:
4142 # x = -2
4243 #
43- # This type of solution, where the factor is repeated, is called a repeated root or a root with multiplicity 2.
44+ # **Method 2: Quadratic Formula**
4445 #
45- # **Method 2: Using the Quadratic Formula**
46+ # The quadratic formula for an equation ax² + bx + c = 0 is:
47+ # x = [-b ± sqrt(b² - 4ac)] / (2a)
4648 #
47- # The quadratic formula solves for x in any equation of the form ax² + bx + c = 0:
48- # x = [-b ± √(b² - 4ac)] / 2a
49- #
50- # 1. **Identify a, b, and c** in the equation x² + 4x + 4 = 0:
51- # * a = 1
52- # * b = 4
53- # * c = 4
54- # 2. **Substitute these values into the formula:**
55- # x = [-4 ± √(4² - 4 * 1 * 4)] / (2 * 1)
56- # 3. **Simplify:**
57- # x = [-4 ± √(16 - 16)] / 2
58- # x = [-4 ± √0] / 2
49+ # 1. In our equation x² + 4x + 4 = 0, we have a=1, b=4, and c=4.
50+ # 2. Substitute these values into the formula:
51+ # x = [-4 ± sqrt(4² - 4 * 1 * 4)] / (2 * 1)
52+ # x = [-4 ± sqrt(16 - 16)] / 2
53+ # x = [-4 ± sqrt(0)] / 2
5954 # x = [-4 ± 0] / 2
60- # 4. **Calculate the result:**
6155 # x = -4 / 2
6256 # x = -2
6357 #
64- # Both methods give the same solution.
58+ # **Method 3: Perfect Square Trinomial**
59+ #
60+ # 1. Notice that the expression x² + 4x + 4 fits the pattern of a perfect square trinomial: a² + 2ab + b², where a=x and b=2.
61+ # 2. We can rewrite the equation as:
62+ # (x + 2)² = 0
63+ # 3. Take the square root of both sides:
64+ # x + 2 = 0
65+ # 4. Solve for x:
66+ # x = -2
67+ #
68+ # All methods lead to the same solution.
6569 #
6670 # **Answer:**
67- # The solution to the equation x² + 4x + 4 = 0 is ** x = -2** .
71+ # The solution to the equation x² + 4x + 4 = 0 is x = -2. This is a repeated root (or a root with multiplicity 2) .
6872 # [END googlegenaisdk_thinking_textgen_with_txt]
6973 return response .text
7074
0 commit comments