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/******************************************************************************************
* CODEWARS BRUTEFORCE PIN CHALLENGE *
* *
* Problem Statement *
* Alright, detective, one of our colleagues successfully observed our target person, *
* Robby the robber. We followed him to a secret warehouse, where we assume to find all *
* the stolen stuff. The door to this warehouse is secured by an electronic combination *
* lock. Unfortunately our spy isn't sure about the PIN he saw, when Robby entered it. *
* *
* The keypad has the following layout: *
* *
* ┌───┬───┬───┐ *
* │ 1 │ 2 │ 3 │ *
* ├───┼───┼───┤ *
* │ 4 │ 5 │ 6 │ *
* ├───┼───┼───┤ *
* │ 7 │ 8 │ 9 │ *
* └───┼───┼───┘ *
* │ 0 │ *
* └───┘ *
* He noted the PIN 1357, but he also said, it is possible that each of the digits he saw *
* could actually be another adjacent digit (horizontally or vertically, but not *
* diagonally). E.g. instead of the 1 it could also be the 2 or 4. And instead of the 5 *
* it could also be the 2, 4, 6 or 8. *
* *
* He also mentioned, he knows this kind of locks. You can enter an unlimited amount of *
* wrong PINs, they never finally lock the system or sound the alarm. That's why we can *
* try out all possible (*) variations. *
* *
* possible in sense: the observed PIN itself & all variations considering the adjacent *
* digits *
* *
* Can you help us to find all those variations? It would be nice to have a function, that*
* returns an array (or a list in Java and C#) of all variations for an observed PIN with *
* a length of 1 to 8 digits. We could name the function getPINs (get_pins in python, *
* GetPINs in C#). But please note that all PINs, the observed one and also the results, *
* must be strings, because of potentially leading '0's. We already prepared some test *
* cases for you. *
* *
* Detective, we count on you! *
* *
* Test Cases *
* Input 1: "8" *
* Output 1: ["5", "7", "8", "9", "0"] *
* *
* Input 2: "11" *
* Output 2: ["11", "22", "44", "12", "21", "14", "41", "24", "42"] *
* *
* Input 3: "369" *
* Output 3: ["339","366","399","658","636","258","268","669","668","266","369","398", *
* "256","296","259","368","638","396","238","356","659","639","666","359","336"*
* ,"299","338","696","269","358","656","698","699","298","236","239"] *
*****************************************************************************************/
function getAdjacentPairs(uniqueNumber) {
let adjancentArray = [
[1, 2, 4],
[2, 1, 3, 5],
[3, 2, 6],
[4, 1, 5, 7],
[5, 2, 8, 4, 6],
[6, 3, 5, 9],
[7, 4, 8],
[8, 5, 0, 7, 9],
[9, 6, 8],
[0, 8],
];
let returnadjancentArray = [];
for (let i = 0; i < uniqueNumber.length; i++)
for (let j = 0; j < adjancentArray.length; j++)
if (uniqueNumber[i] == adjancentArray[j][0])
returnadjancentArray.push(adjancentArray[j]);
return returnadjancentArray;
}
function generatePINCombination(adjacentNumberArray) {
let ans = [];
let flag = 0;
for (let i = 0; i < adjacentNumberArray.length; i++) {
if (i != adjacentNumberArray.length - 1) {
flag = 1;
if (i === 0)
ans = makeArrayCombination(
adjacentNumberArray[i],
adjacentNumberArray[i + 1]
);
else ans = makeArrayCombination(ans, adjacentNumberArray[i + 1]);
} else if (flag === 0) ans = adjacentNumberArray[0].map((m) => String(m));
}
return ans;
}
function makeArrayCombination(arr1, arr2) {
let temp = [];
for (let i = 0; i < arr1.length; i++)
for (let j = 0; j < arr2.length; j++)
temp.push(String(arr1[i]) + String(arr2[j]));
return temp;
}
function getPINs(observed) {
let uniqueNumber = observed.split("");
let adjacentNumberArray = getAdjacentPairs(uniqueNumber);
let ans = generatePINCombination(adjacentNumberArray);
return ans;
}