Try a jldoctest

Author: mikeingold

docs/src/tutorial.md

@@ -81,12 +81,14 @@ integral(f, curve)  # -> Approximately 2π Ω
 The alias function `lineintegral` works for this geometry since it has one
 parametric dimension. However, the aliases `surfaceintegral` and `volumeintegral`
 will throw an `ArgumentError` since the geometry is not a surface or volume.
-```@example tutorial
+```jldoctest tutorial
 lineintegral(f, curve)  # -> Approximately 2π Ω
 
 surfaceintegral(f, curve)  # -> throws ArgumentError
+ERROR: ArgumentError: Performing a surface integral on a geometry with 1 parametric dimensions not supported.
 
 volumeintegral(f, curve)  # -> throws ArgumentError
+ERROR: ArgumentError: Performing a volume integral on a geometry with 1 parametric dimensions not supported.
 ```
 
 An `IntegrationRule` with settings can also be manually specified. The following