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Hello, I am experiencing an error that can be reproduced with the following lines:
using Interpolations, CUDA, Adapt
N = 5
x = range(0f0, 1f0, N)
y = rand(Float32, N)
itp = interpolate((x,), y, Gridded(Linear()))
cuitp = adapt(CuArray{Float32}, itp);
xp = range(0f0, 1f0, N)
u = cuitp.(xp)
This works with CUDA and AMDGPU arrays but, when:
cuitp = adapt(MtlArray{Float32}, itp);or:
cuitp = adapt(oneArray{Float32}, itp);The following errors appear:
ERROR: LoadError: InvalidIRError: compiling MethodInstance for (::Metal.var"#broadcast_linear#202")(::Metal.MtlDeviceVector{Float32, 1}, ::Base.Broadcast.Broadcasted{Metal.MtlArrayStyle{1, Metal.MTL.Private}, Tuple{Base.OneTo{Int64}}, Interpolations.GriddedInterpolation{Float32, 1, Metal.MtlDeviceVector{Float32, 1}, Interpolations.Gridded{Interpolations.Linear{Interpolations.Throw{Interpolations.OnGrid}}}, Tuple{StepRangeLen{Float32, Float32, Float32, Int64}}}, Tuple{Base.Broadcast.Extruded{StepRangeLen{Float32, Float32, Float32, Int64}, Tuple{Bool}, Tuple{Int64}}}}) resulted in invalid LLVM IRERROR: LoadError: InvalidIRError: compiling MethodInstance for (::GPUArrays.var"#34#36")(::oneAPI.oneKernelContext, ::oneAPI.oneDeviceVector{Float32, 1}, ::Base.Broadcast.Broadcasted{oneAPI.oneArrayStyle{1, oneAPI.oneL0.DeviceBuffer}, Tuple{Base.OneTo{Int64}}, Interpolations.GriddedInterpolation{Float32, 1, oneAPI.oneDeviceVector{Float32, 1}, Interpolations.Gridded{Interpolations.Linear{Interpolations.Throw{Interpolations.OnGrid}}}, Tuple{StepRangeLen{Float32, Float32, Float32, Int64}}}, Tuple{Base.Broadcast.Extruded{oneAPI.oneDeviceVector{Float32, 1}, Tuple{Bool}, Tuple{Int64}}}}, ::Int64) resulted in invalid LLVM IRFull stacktrace is here.
I do not know if this is a bug from Metal and oneAPI or if it is the expected behaviour.
What is strange is the fact that it only fails for Metal and oneAPI.
Note that this works for all backends:
using Interpolations, CUDA, Adapt
N = 5
x = collect(range(0f0, 1f0, N))
y = rand(Float32, N)
itp = interpolate((x,), y, Gridded(Linear()))
cuitp = adapt(CuArray{Float32}, itp);
xp = rand(N); xp = adapt(CuArray{Float32}, xp)
u = cuitp.(xp)But I need input nodes to be ranges instead of arrays, to avoid extra allocations.
Thank you, I really appreciate what this package offers and it would be awesome to put a solution to this π
Cheers,
Pablo
mkittimkitti
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