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Updated BesselZeros.ipynb
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examples/BesselZeros.ipynb

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@@ -127,7 +127,7 @@
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"Let $j_{\\nu,m}'$ denote the $m$th zero of the derivative $J_\\nu'(z)$.\n",
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"Asymptotically it holds\n",
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"\n",
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"$$\\mathop{j_{\\nu,m}}\\nolimits',\\mathop{y_{\\nu,m}}\\nolimits'\\sim b-\\frac{\\mu+%\n",
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"$$\\mathop{j_{\\nu,m}}\\nolimits'\\sim b-\\frac{\\mu+%\n",
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"3}{8b}-\\frac{4(7\\mu^{2}+82\\mu-9)}{3(8b)^{3}}-\\frac{32(83\\mu^{3}+2075\\mu^{2}-30%\n",
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"39\\mu+3537)}{15(8b)^{5}}-\\frac{64(6949\\mu^{4}+2\\;96492\\mu^{3}-12\\;48002\\mu^{2}%\n",
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"+74\\;14380\\mu-58\\;53627)}{105(8b)^{7}}-\\cdots,$$\n",
@@ -277,7 +277,7 @@
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"First we use __BigFloat__ with precision 113 bits, exactly the precison of Flot128:"
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"First we use __BigFloat__ with precision 113 bits, exactly the precison of Float128:"
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]
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},
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{
@@ -561,7 +561,7 @@
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"Next we do the same as above with the zeros of the derivatives of the Bessel functions."
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"Now we do the same as above with the zeros of the derivatives of the Bessel functions."
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]
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},
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{
@@ -701,11 +701,22 @@
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},
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{
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"cell_type": "code",
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"execution_count": null,
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"execution_count": 21,
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"metadata": {
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"collapsed": false
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},
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"outputs": [],
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"outputs": [
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{
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"data": {
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"text/plain": [
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"4.85294980909585503117445493628658640e-13"
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]
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},
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"execution_count": 21,
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"metadata": {},
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"output_type": "execute_result"
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}
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],
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"source": [
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"maximum((j1_f128-j1_f64)./j1_f128)"
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]

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