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Can we use MELD on single replicate #56

@Rohit-Satyam

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@Rohit-Satyam

Hi Developers!!

We have single-cell data for two-time points each containing control and knockout sample (t1_ctr, t1_ko, t2_ctr,tr_ko). We wish to find out how if the knockout cells are arrested in lifecycle more at time T1 or at Time T2. Is this achievable because we have one replicate per time_period?

Also, in the tutorial and the following code chunk:

with Parallel(n_jobs=36) as p:
    for knn in knn_range:
        # doing this outside the parallel loop because building the graph takes the longest
        benchmarker.fit_graph(adata.X, knn=knn)
        print(knn)
        curr_results = p(delayed(simulate_pdf_calculate_likelihood)(benchmarker, seed, beta) \
                                       for seed in range(25) for beta in beta_range)
        curr_results = pd.DataFrame(curr_results, columns = ['MSE', 'seed', 'beta', 'knn'])
        results.append(curr_mse)

what is adata.X as it is giving an error

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