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update: 添加问题“2614.对角线上的质数”的代码和题解(#823)
feat: under merge标签(#821) Signed-off-by: LetMeFly666 <[email protected]>
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.commitmsg

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docs: 柠檬微趣题解 - 小改
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word: en words
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feat: under merge标签(#821)

.gitignore

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del*
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OtherSource
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__pycache__
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# 因为邮件上说不让泄露面试内容,所以自己总结总结看看好了
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字节后端开发-搜索-一面.md
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# Prerequisites
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*.d

Codes/2614-prime-in-diagonal.cpp

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/*
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* @Author: LetMeFly
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* @Date: 2025-03-18 23:40:09
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* @LastEditors: LetMeFly.xyz
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* @LastEditTime: 2025-03-18 23:43:36
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*/
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#ifdef _WIN32
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#include "_[1,2]toVector.h"
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#endif
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class Solution {
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private:
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bool isPrime(int n) {
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if (n < 2) {
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return false;
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}
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int k = sqrt(n);
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for (int i = 2; i <= k; i++) {
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if (n % i == 0) {
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return false;
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}
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}
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return true;
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}
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public:
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int diagonalPrime(vector<vector<int>>& nums) {
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int ans = 0;
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for (int i = 0; i < nums.size(); i++) {
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if (isPrime(nums[i][i])) {
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ans = max(ans, nums[i][i]);
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}
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if (isPrime(nums[i][nums.size() - i - 1])) {
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ans = max(ans, nums[i][nums.size() - i - 1]);
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}
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}
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return ans;
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}
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};

Codes/2614-prime-in-diagonal.go

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/*
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* @Author: LetMeFly
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* @Date: 2025-03-18 23:55:55
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* @LastEditors: LetMeFly.xyz
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* @LastEditTime: 2025-03-18 23:58:46
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*/
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package main
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func isPrime2614(n int) (ans bool) {
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if n < 2 {
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return
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}
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for i := 2; i * i <= n; i++ {
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if n % i == 0 {
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return
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}
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}
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return true
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}
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func diagonalPrime(nums [][]int) (ans int) {
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for i := range nums {
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if isPrime2614(nums[i][i]) {
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ans = max(ans, nums[i][i])
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}
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if isPrime2614(nums[i][len(nums) - i - 1]) {
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ans = max(ans, nums[i][len(nums) - i - 1])
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}
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}
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return
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}

Codes/2614-prime-in-diagonal.java

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/*
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* @Author: LetMeFly
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* @Date: 2025-03-18 23:50:23
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* @LastEditors: LetMeFly.xyz
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* @LastEditTime: 2025-03-18 23:55:24
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*/
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class Solution {
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private boolean isPrime(int n) {
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if (n < 2) {
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return false;
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}
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int k = (int)Math.sqrt(n);
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for (int i = 2; i <= k; i++) {
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if (n % i == 0) {
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return false;
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}
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}
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return true;
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}
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public int diagonalPrime(int[][] nums) {
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int ans = 0;
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for (int i = 0; i < nums.length; i++) {
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if (isPrime(nums[i][i])) {
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ans = Math.max(ans, nums[i][i]);
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}
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if (isPrime(nums[i][nums.length - i - 1])) {
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ans = Math.max(ans, nums[i][nums.length - i - 1]);
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}
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}
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return ans;
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}
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}

Codes/2614-prime-in-diagonal.py

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'''
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Author: LetMeFly
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Date: 2025-03-18 23:46:52
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LastEditors: LetMeFly.xyz
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LastEditTime: 2025-03-18 23:48:14
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'''
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from typing import List
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from math import sqrt
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class Solution:
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def isPrime(self, n: int) -> bool:
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if n < 2:
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return False
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for i in range(2, int(sqrt(n)) + 1):
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if n % i == 0:
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return False
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return True
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def diagonalPrime(self, nums: List[List[int]]) -> int:
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ans = 0
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for i in range(len(nums)):
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if self.isPrime(nums[i][i]):
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ans = max(ans, nums[i][i])
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if self.isPrime(nums[i][len(nums) - i - 1]):
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ans = max(ans, nums[i][len(nums) - i - 1])
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return ans
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/*
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* @Author: LetMeFly
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* @Date: 2025-03-18 21:00:06
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* @LastEditors: LetMeFly.xyz
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* @LastEditTime: 2025-03-18 21:05:19
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*/
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#include <iostream>
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using namespace std;
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struct Node {
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int val;
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Node* next;
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Node(int val, Node* next): val(val), next(next) {};
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};
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void debug(Node* head) {
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head = head->next;
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while (head) {
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cout << head->val << ',';
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head = head->next;
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}
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puts("");
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}
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void debug(Node* from, Node* to) {
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while (from != to) {
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cout << from->val << ',';
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from = from->next;
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}
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if (to) {
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cout << to->val << endl;
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}
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}
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void realRev(Node* last, Node* to) {
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debug(last, to);
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// return;
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int cnt = 0;
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Node* p = last->next;
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// last->next = nullptr;
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while (p != to) {
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cnt++;
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cout << p->val << endl;
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if (cnt > 15) {
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break;
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}
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Node* next = p->next;
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p->next = last;
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last = p;
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p = next;
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}
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to->next = last;
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}
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void rev(Node* p, int k) {
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Node* last = p;
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int cnt = 0;
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while (p) {
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p = p->next;
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if (p) {
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cnt++;
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}
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if (cnt == k) {
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// reverse
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Node* next = p->next;
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realRev(last, p);
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last->next = next;
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last = p;
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cnt = 0;
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p = next;
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}
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}
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}
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/*
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3 8
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1 2 3 4 5 6 7 8
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*/
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int main() {
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// char str[3];
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// std::cin>>str;
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// std::cout << "hello world" << std::endl;
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int k, n, t;
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cin >> k >> n;
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Node* head = new Node(0, nullptr);
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Node* p = head;
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for (int i = 0; i < n; i++) {
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cin >> t;
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Node* thisNode = new Node(t, nullptr);
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p->next = thisNode;
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p = p->next;
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}
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rev(head, k);
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debug(head);
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return 0;
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}

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