Add missing documentation for a recently introduced check.

Author: Xazax-hun

docs/code-quality/c6392.md

@@ -0,0 +1,60 @@
+---
+description: "Learn more about: Warning C6392"
+title: Warning C6392
+ms.date: 03/06/2024
+f1_keywords: ["C6392", "STREAM_OUTPUT_VOID_PTR", "__STREAM_OUTPUT_VOID_PTR"]
+helpviewer_keywords: ["C6392"]
+---
+# Warning C6392
+
+> This expression will write the value of the pointer to the stream; if this is intentional, add an explicit cast to 'void *'
+
+This rule was added in Visual Studio 2022 17.8.
+
+## Remarks
+
+In C++, we have streams of wide characters, like `std::wostringstream`, and streams of non-wide characters like `std::ostringstream`. Trying to print a wide character literal to a non-wide string will call the `void*` overload of `operator<<`. This results in printing the address of the wide character literal instead of the value.
+
+Code analysis name: `STREAM_OUTPUT_VOID_PTR`
+
+## Example
+
+In the following code snippet, we will print the value of the pointer to the standard output instead of the string `"Foo"`:
+
+```cpp
+#include <iostream>
+
+int main() {
+    std::cout << L"Foo\n"; // Warning: C6392
+}
+```
+
+There are multiple ways to fix this error. If printing the pointer value is unintended, we can use a non-wide string literal:
+
+```cpp
+#include <iostream>
+
+int main() {
+    std::cout << "Foo\n"; // No warning.
+}
+```
+
+Alternatively, we can use a wide stream:
+
+```cpp
+#include <iostream>
+
+int main() {
+    std::wcout << L"Foo\n"; // No warning.
+}
+```
+
+If the behavior is intentional, we can silence the warning using an explicit cast:
+
+```cpp
+#include <iostream>
+
+int main() {
+    std::cout << static_cast<void*>(L"Foo\n"); // No warning.
+}
+```

docs/code-quality/toc.yml

@@ -481,6 +481,8 @@ items:
     href: ../code-quality/c6389.md
   - name: Warning C6390
     href: ../code-quality/c6390.md
+  - name: Warning C6392
+    href: ../code-quality/c6392.md
   - name: Warning C6393
     href: ../code-quality/c6393.md
   - name: Warning C6394