@@ -20,10 +20,10 @@ in order that a simulation is successful:
2020 otherwise a variable step-size integrator will typically fail. The reason is that
2121 the penetration depth is computed from the difference of tolerance-controlled
2222 variables and the precision will be not sufficient if a higher tolerance will be
23- used because the penetration depth of hard contact materials
23+ used because the penetration depth of hard contact materials
2424 is in the order of `` 10^{-5} .. 10^{-6}~ m `` .
2525 A relative tolerancie of `` 10^{-5} `` might be used, if the heuristic
26- elastic contact reduction factor is set to `` k_{red} = 10^{4} `` (see [ Material constants] ( @ref ) below).
26+ elastic contact reduction factor is set to `` k_{red} = 10^{- 4} `` (see [ Material constants] ( @ref ) below).
2727
2828- A reasonable reliable simulation requires that objects have only
2929 * point contact* , since otherwise the contact point can easily `` jump `` between
@@ -68,7 +68,7 @@ tolerance of ``10^{-8}`` needs to be used for the integration, in order that
6868the penetration depth is computed with 2 or 3 significant digits.
6969To improve simulation speed, factor `` k_{red} ``
7070reduces the stiffness of the contact and therefore enlarges the
71- penetration depth. If `` k_{red} `` is for example set to `` 10^{4} `` , the penetration
71+ penetration depth. If `` k_{red} `` is for example set to `` 10^{- 4} `` , the penetration
7272depth might be in the order of `` 10^{-3} m `` and then a relative tolerance
7373of `` 10^{-5} `` might be sufficient. In many cases, the essential response
7474characteristic is not changed (just the penetration depth is larger),
@@ -252,4 +252,3 @@ similar responses:
252252 [ A review of continuous contact-force models in multibody dynamics] ( https://doi.org/10.1016/j.ijmecsci.2018.07.010 ) .
253253 International Journal of Mechanical Sciences, Volume 145,
254254 Sept., pages 171-187.
255-
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