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fix a few typos
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content/first-order-logic/natural-deduction/quantifier-rules.tex

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@@ -49,7 +49,7 @@ \subsection{Rules for $\lexists$}
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\DisplayProof
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\end{defish}
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Again, $t$ is a closed term, and $a$ is a constant which does not
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Again, $t$ is a closed term, and $a$ is !!a{constant} which does not
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occur in the premise $\lexists[x][!A(x)]$, in the conclusion~$!C$, or
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any assumption which is !!{undischarged} in the !!{derivation}s ending
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with the two premises (other than the assumptions $!A(a)$). We call

content/incompleteness/representability-in-q/introduction.tex

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& \lforall[x][\lforall[y][(x < y \liff \lexists[z][\eq[(z' + x)][y]])]] \tag{$!Q_8$}
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\end{align*}
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For each natural number $n$, define the numeral $\num{n}$ to be the
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term $0^{\prime\prime\ldots\prime}$ where there are $n$ tick marks in
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term $\Obj{0}^{\prime\prime\ldots\prime}$ where there are $n$ tick marks in
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all. So, $\num{0}$ is the !!{constant}~$\Obj{0}$ by itself, $\num{1}$
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is $\Obj{0}'$, $\num{2}$ is $\Obj{0}''$, etc.
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content/lambda-calculus/introduction/minimization.tex

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\olsection{The \usetoken{S}{lambda definable} Functions are Closed under Minimization}
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\begin{lem}
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Suppose $f(x,y)$ is primitive recursive. Let $g$ be defined by
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Suppose $f(x,y)$ is !!{lambda definable}. Let $g$ be defined by
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\[
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g(x) \simeq \umin{y}{f(x,y)}.
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\]
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$F(\num{m}, \num{n})$ reduces to any other numeral.
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To finish off the proof, let $G$ be $\lambd[x][H(\num 0)]$. Then $G$
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!!{lambda define}s $g$; in other words, for every $m$, $G(\num m)$ reduces to
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reduces to $\overline {g(m)}$, if $g(m)$ is defined, and has no
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normal form otherwise.
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!!{lambda define}s~$g$; in other words, for every~$m$, $G(\num m)$
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reduces to~$\overline {g(m)}$, if $g(m)$ is defined, and has no normal
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form otherwise.
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\end{proof}
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\end{document}

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