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Fix typos in proof of Theorem 22.36
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content/first-order-logic/axiomatic-deduction/soundness.tex

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@@ -69,7 +69,7 @@
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ponens, then there are !!{formula}s $!B$ and $!B \lif !A$ in the
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!!{derivation}, and the induction hypothesis applies to the part of
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the !!{derivation} ending in those !!{formula}s (since they contain at
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least one fewer steps justified by an inference). So, by induction
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least one fewer step justified by an inference). So, by induction
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hypothesis, $\Gamma \Entails !B$ and $\Gamma \Entails !B \lif
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!A$. Then $\Gamma \Entails !A$ by
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\iftag{FOL}
@@ -80,7 +80,7 @@
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\QR. Then that step has the form $!C \lif \lforall[x][B(x)]$ and
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there is a preceding step $!C \lif !B(c)$ with $c$ not in $\Gamma$,
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$!C$, or $\lforall[x][B(x)]$. By induction hypothesis, $\Gamma
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\Entails !C \lif \lforall[x][B(x)]$. By
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\Entails !C \lif !B(c)$. By
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\olref[syn][sem]{thm:sem-deduction}, $\Gamma \cup \{!C\} \Entails
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!B(c)$.
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@@ -95,9 +95,9 @@
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not occur in~$\Gamma$ or~$!C$, $\Sat{M'}{\Gamma \cup \{!C\}}$ by
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\olref[syn][ext]{cor:extensionality-sent}. Since $\Gamma \cup \{!C\}
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\Entails !B(c)$, $\Sat{M'}{B(c)}$. Since $!B(c)$ is !!a{sentence},
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$\Sat{M}{!B(c)}[s]$ by
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$\Sat{M'}{!B(c)}[s]$ by
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\olref[syn][ass]{prop:sentence-sat-true}. $\Sat{M'}{!B(x)}[s]$ iff
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$\Sat{M'}{!B(c)}$ by \olref[syn][ext]{prop:ext-formulas} (recall that
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$\Sat{M'}{!B(c)}[s]$ by \olref[syn][ext]{prop:ext-formulas} (recall that
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$!B(c)$ is just $\Subst{!B(x)}{c}{x}$). So,
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$\Sat{M'}{!B(x)}[s]$. Since $c$ does not occur in~$!B(x)$, by
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\olref[syn][ext]{prop:extensionality}, $\Sat{M}{!B(x)}[s]$. But $s$

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