|
| 1 | +r""" |
| 2 | +Non-rigid structure-from-motion (NRSfM) |
| 3 | +======================================= |
| 4 | +In computer vision, structure-from-motion (SfM) is an imaging technique for |
| 5 | +estimating three-dimensional structures from two-dimensional images. Theoretically, |
| 6 | +the problem is generally well-posed when considering rigid objects, meaning |
| 7 | +that the objects do not move or deform in the scene. However, non-static scenes |
| 8 | +are still relevant and have gained increased popularity among researchers in |
| 9 | +recent years. This is known as *non-rigid structure-from-motion*. |
| 10 | +
|
| 11 | +In this tutorial, we will consider motion capture (MOCAP). This is a special |
| 12 | +case, where we use images from multiple camera views to compute the 3D positions |
| 13 | +of specifically designed markers that track the motion of a person (or object) |
| 14 | +performing various tasks. |
| 15 | +
|
| 16 | +Non-rigid shapes |
| 17 | +**************** |
| 18 | +To make the problem well-posed, one has to control the complexity of |
| 19 | +the deformations using some minor assumptions on the possible space of object |
| 20 | +shapes. This is not a weird thing to do: consider e.g. the human body, |
| 21 | +we have different joints that bend and turn in a finite amount of ways; the |
| 22 | +skeleton itself is rigid and not capable of such deformations. For this reason, |
| 23 | +Bregler et al. [1]_ suggested that all movements (or shapes) can be represented |
| 24 | +by a low-dimensional basis. In the context of motion capture, this means that |
| 25 | +every movement a person does can be considered a combination of core movements |
| 26 | +(or basis shapes). |
| 27 | +
|
| 28 | +Mathematically speaking, this translates to any motion being a linear combination |
| 29 | +of the basis shapes, i.e. assuming there are :math:`K` basis shapes, any non-rigid |
| 30 | +shape :math:`X_i` can be written as |
| 31 | +
|
| 32 | + .. math:: |
| 33 | + X_i = \sum_{i=1}^K c_{ik}B_k |
| 34 | +
|
| 35 | +where :math:`c_{ik}` are the basis coefficients and :math:`B_k` are the basis shapes. |
| 36 | +Here, :math:`X_i` is a :math:`3\times N` matrix where each column is a point in |
| 37 | +3D space. |
| 38 | +
|
| 39 | +The CMU MOCAP dataset |
| 40 | +********************* |
| 41 | +Let us first try to understand the data we are given. We will use the *Pickup* |
| 42 | +instance from the CMU MOCAP dataset, which depicts a person picking something |
| 43 | +up from the floor. |
| 44 | +""" |
| 45 | + |
| 46 | +import matplotlib.pyplot as plt |
| 47 | +import matplotlib.animation as animation |
| 48 | +import numpy as np |
| 49 | +import scipy as sp |
| 50 | + |
| 51 | + |
| 52 | +plt.close('all') |
| 53 | +np.random.seed(0) |
| 54 | +data = np.load('../testdata/mocap.npz', allow_pickle=True) |
| 55 | +X_gt = data['X_gt'] |
| 56 | +markers = data['markers'].item() |
| 57 | + |
| 58 | +############################################################################### |
| 59 | +# First we view the first 3D poses. In order to easily visualize the person, we |
| 60 | +# draw a skeleton between the markers corresponding to certain body parts. Note |
| 61 | +# that these are not used in any other way. |
| 62 | + |
| 63 | + |
| 64 | +def plot_first_3d_pose(ax, X, color='b', marker='o', linecolor='k'): |
| 65 | + ax.scatter(X[0, :], X[1, :], X[2, :], color, marker=marker) |
| 66 | + for j, ind in enumerate(markers.values()): |
| 67 | + ax.plot(X[0, ind], X[1, ind], X[2, ind], '-', color=linecolor) |
| 68 | + ax.set_box_aspect(np.ptp(X[:3, :], axis=1)) |
| 69 | + ax.view_init(20, 25) |
| 70 | + |
| 71 | + |
| 72 | +fig = plt.figure() |
| 73 | +ax = fig.add_subplot(projection='3d') |
| 74 | +plot_first_3d_pose(ax, X_gt) |
| 75 | +plt.tight_layout() |
| 76 | + |
| 77 | +############################################################################### |
| 78 | +# Now, we turn the attention to the data the algorithm is given, which is a |
| 79 | +# sequence of 2D images from varying views. The goal is to recreate the 3D |
| 80 | +# points, such as in the example above, from all timestamps. |
| 81 | + |
| 82 | +M = data['M'] |
| 83 | +F = int(X_gt.shape[0] / 3) |
| 84 | + |
| 85 | + |
| 86 | +def _update(f: int): |
| 87 | + X = M[2 * f:2 * f + 2, :] |
| 88 | + lines[0].set_data(X[0, :], X[1, :]) |
| 89 | + for j, ind in enumerate(markers.values()): |
| 90 | + lines[j + 1].set_data(X[0, ind], X[1, ind]) |
| 91 | + return lines |
| 92 | + |
| 93 | + |
| 94 | +fig, ax = plt.subplots() |
| 95 | +lines = ax.plot([], [], 'r.') |
| 96 | +for _ in range(len(markers)): |
| 97 | + lines.append(ax.plot([], [], 'k-')[0]) |
| 98 | +ax.set(xlim=(-2.5, 2.5), ylim=(-3.5, 3.5)) |
| 99 | +ax.set_aspect('equal') |
| 100 | + |
| 101 | +ani = animation.FuncAnimation(fig, _update, F, interval=25, blit=True) |
| 102 | + |
| 103 | + |
| 104 | +############################################################################### |
| 105 | +# Note that these are the 2D image correspondences and that the image view is |
| 106 | +# constantly changing as it is spinning around. Such motion can be modeled |
| 107 | +# with orthographic cameras, which we will discuss next. |
| 108 | +# |
| 109 | +# Orthographic projections |
| 110 | +# ************************ |
| 111 | +# Assuming that we know the pose of the camera from which the image was taken |
| 112 | +# the corresponding 2D image point can be obtained. In the case of rotations, |
| 113 | +# we assume the cameras are orthographic, meaning that the image points :math:`x_i` |
| 114 | +# are obtained from the relation |
| 115 | +# |
| 116 | +# .. math:: |
| 117 | +# x_i = R_iX_i |
| 118 | +# |
| 119 | +# where :math:`R_i` is a :math:`2\times 3` matrix fulfilling :math:`R_iR_i^T=I`. |
| 120 | +# Essentially, the :math:`R_i` matrices consists of the top two rows of the |
| 121 | +# corresponding rotation matrix. |
| 122 | +# |
| 123 | +# Now, the task at hand is essentially the inverse problem: to reconstruct the |
| 124 | +# 3D points for each point in time from these 2D images. |
| 125 | +# |
| 126 | +# Treating NRSfM as a low-rank factorization problem |
| 127 | +# ************************************************** |
| 128 | +# One of the main novelties of the paper by Dai et al. [2]_ is to reshape and |
| 129 | +# stack the non-rigid shapes :math:`X_i` in a way that allows us to treat the |
| 130 | +# problem using methods from low-rank factorization. This is done in the following |
| 131 | +# way: first concatenate all rows of :math:`X_i` creating a vector |
| 132 | +# :math:`X^\sharp_i` of size :math:`1\times 3N`. Secondly, assuming there are in |
| 133 | +# total :math:`F` non-rigid shapes we create the matrix :math:`X^\sharp` of size |
| 134 | +# :math:`F\times 3N` by stacking all :math:`X^\sharp_i`. This enables us to decompose |
| 135 | +# the newly created matrix :math:`X^\sharp=CB^\sharp` in the low-rank factors |
| 136 | +# consisting of the shape coefficients :math:`C` and the basis shapes :math:`B^\sharp` |
| 137 | +# (constructed in the same way as :math:`X^\sharp`). |
| 138 | +# |
| 139 | +# Now, let us implement and visualize this approach. |
| 140 | + |
| 141 | + |
| 142 | +def stack(X: np.ndarray): |
| 143 | + return np.hstack((X[::3, :], X[1::3, :], X[2::3, :])) |
| 144 | + |
| 145 | + |
| 146 | +Xi = np.arange(15).reshape((3, 5)) |
| 147 | +fig, ax = plt.subplots(1, 2) |
| 148 | +ax[0].matshow(Xi) |
| 149 | +ax[0].set_title(r'$X_i$') |
| 150 | +ax[0].axis('off') |
| 151 | +ax[1].matshow(stack(Xi)) |
| 152 | +ax[1].set_title(r'$X_i^\sharp$') |
| 153 | +ax[1].axis('off') |
| 154 | +plt.tight_layout() |
| 155 | + |
| 156 | +############################################################################### |
| 157 | +# Furthermore, we introduce the inverse |
| 158 | +# operation, such that :math:`X=\mathcal{U}(X^\sharp)`, where |
| 159 | +# :math:`\mathcal{U}` is the "unstacking" operator. |
| 160 | + |
| 161 | + |
| 162 | +def unstack(Xs: np.ndarray): |
| 163 | + """Inverse operation of stack.""" |
| 164 | + m, n = Xs.shape |
| 165 | + m *= 3 |
| 166 | + n //= 3 |
| 167 | + X = np.zeros((m, n), dtype=Xs.dtype) |
| 168 | + X[::3] = Xs[:, :n] |
| 169 | + X[1::3] = Xs[:, n:2*n] |
| 170 | + X[2::3] = Xs[:, 2*n:3*n] |
| 171 | + return X |
| 172 | + |
| 173 | +############################################################################### |
| 174 | +# In many cases, the necessary amount of basis shapes is not known |
| 175 | +# *a priori*. Therefore, a suitable objective to try to minimize is |
| 176 | +# |
| 177 | +# .. math:: |
| 178 | +# \argmin_X \mu \rank(X^\sharp) + \frac{1}{2}\sum_{i=1}^F\|R_iX_i - x_i\|_2^2 |
| 179 | +# |
| 180 | +# or, equivalently, |
| 181 | +# |
| 182 | +# .. math:: |
| 183 | +# \argmin_X \mu \rank(X^\sharp) + \frac{1}{2}\|RX - M\|_F^2 |
| 184 | +# |
| 185 | +# where :math:`R` is a block-diagonal matrix with :math:`R_i` on the main diagonal, |
| 186 | +# whereas :math:`X` and :math:`M` are the concatenations of :math:`X_i` and |
| 187 | +# :math:`x_i`, respectively. |
| 188 | +# |
| 189 | +# Since the rank function is non-convex and discontinuous, it is often replaced |
| 190 | +# by a relaxation. In [2]_ the *nuclear norm* :math:`\|\cdot\|_{*}` was used, i.e. |
| 191 | +# we seek to minimize |
| 192 | +# |
| 193 | +# .. math:: |
| 194 | +# \argmin_X \mu \|X^\sharp\|_{*} + \frac{1}{2}\|RX - M\|_F^2 \; . |
| 195 | +# |
| 196 | +# There are some theoretical justifications for this specific choice of relaxation, |
| 197 | +# e.g. the nuclear norm is the convex envelope of the rank function under |
| 198 | +# curtain assumptions [3]_. |
| 199 | +# |
| 200 | +# Solving the relaxed problem |
| 201 | +# *************************** |
| 202 | +# We will now show how to solve this problem using splitting schemes. Specifically, |
| 203 | +# we will use :class:`pyproximal.ADMM` and re-write the objective as |
| 204 | +# |
| 205 | +# .. math:: |
| 206 | +# \argmin_{X, Z} \mu \|Z^\sharp\|_{*} + \frac{1}{2}\|RX - M\|_F^2, |
| 207 | +# |
| 208 | +# and add the constraint :math:`X=Z`. This way, the proximal operators |
| 209 | +# are simply those of the (stacked) nuclear norm and the Frobenius norm. |
| 210 | +# We implement these next: |
| 211 | + |
| 212 | +from pyproximal.ProxOperator import _check_tau |
| 213 | +from pyproximal import Nuclear, ProxOperator |
| 214 | + |
| 215 | + |
| 216 | +class BlockDiagFrobenius(ProxOperator): |
| 217 | + r"""Proximal operator for 1/2 * ||RX - M||_F^2 where R is block-diagonal. |
| 218 | + Note: You could also wrap pyproximal.L2, but this class is used here in |
| 219 | + this tutorial to increase legibility. |
| 220 | + """ |
| 221 | + def __init__(self, dim, R, M): |
| 222 | + super().__init__(None, False) |
| 223 | + self.dim = dim |
| 224 | + self.R = R |
| 225 | + self.M = M |
| 226 | + |
| 227 | + def __call__(self, x): |
| 228 | + X = x.reshape(self.dim) |
| 229 | + return 0.5 * np.linalg.norm(self.R @ X - self.M, 'fro') ** 2 |
| 230 | + |
| 231 | + @_check_tau |
| 232 | + def prox(self, x, tau): |
| 233 | + X = x.reshape(self.dim) |
| 234 | + Y = np.zeros_like(X) |
| 235 | + for f, Rf in enumerate(self.R): |
| 236 | + Y[3 * f: 3 * f + 3, :] = np.linalg.solve( |
| 237 | + tau * Rf.T @ Rf + np.eye(3), |
| 238 | + tau * Rf.T @ self.M[2 * f:2 * f + 2, :] + X[3 * f: 3 * f + 3, :] |
| 239 | + ) |
| 240 | + return Y.flatten() |
| 241 | + |
| 242 | + |
| 243 | +class StackedNuclear(Nuclear): |
| 244 | + r"""Proximal operator for the stacked nuclear norm.""" |
| 245 | + def __init__(self, dim, sigma=1.): |
| 246 | + super().__init__(dim, sigma) |
| 247 | + self.unstacked_dim = (dim[0] * 3, dim[1] // 3) |
| 248 | + |
| 249 | + def __call__(self, x): |
| 250 | + X = stack(x.reshape(self.unstacked_dim)) |
| 251 | + return super().__call__(X.ravel()) |
| 252 | + |
| 253 | + def prox(self, x, tau): |
| 254 | + X = stack(x.reshape(self.unstacked_dim)) |
| 255 | + x = super().prox(X.ravel(), tau) |
| 256 | + X = unstack(x.reshape(self.dim)) |
| 257 | + return X.ravel() |
| 258 | + |
| 259 | + |
| 260 | +############################################################################### |
| 261 | +# Now we are ready to solve the problem using ADMM. |
| 262 | + |
| 263 | +from pyproximal.optimization.primal import ADMM |
| 264 | + |
| 265 | + |
| 266 | +mu = 1 |
| 267 | +R = data['R'] |
| 268 | +Rblk = sp.linalg.block_diag(*R) |
| 269 | +M = Rblk @ X_gt |
| 270 | +N = M.shape[1] |
| 271 | +normal_size = (3*F, N) |
| 272 | +stacked_size = (F, 3*N) |
| 273 | +X0 = np.zeros(normal_size) |
| 274 | +proxf = BlockDiagFrobenius(normal_size, R, M) |
| 275 | +proxg = StackedNuclear(stacked_size, mu) |
| 276 | +X_rec = ADMM(proxf, proxg, x0=X0.flatten(), tau=0.9, niter=200)[0] |
| 277 | +X_rec = X_rec.reshape(normal_size) |
| 278 | + |
| 279 | +############################################################################### |
| 280 | +# Let us compare the results with the ground truth data. |
| 281 | +fig = plt.figure() |
| 282 | +ax = fig.add_subplot(projection='3d') |
| 283 | +plot_first_3d_pose(ax, X_gt) |
| 284 | +plot_first_3d_pose(ax, X_rec, color='r', marker='v', linecolor='r') |
| 285 | +plt.tight_layout() |
| 286 | + |
| 287 | +############################################################################### |
| 288 | +# Furthermore, we compute some statistics on the reconstruction performance. You |
| 289 | +# can vary the regulation strength :math:`\mu` to see if you can achieve better |
| 290 | +# performance yourself! |
| 291 | +print(f'Datafit: {np.linalg.norm(Rblk @ X_rec - M, "fro")}') |
| 292 | +print(f'Distance to GT: {np.linalg.norm(X_rec - X_gt, "fro")}') |
| 293 | + |
| 294 | +############################################################################### |
| 295 | +# One issue with the nuclear norm is that you have the hyperparameter |
| 296 | +# :math:`\mu` that regulates the impact of the datafit vs. model assumption. |
| 297 | +# When :math:`\mu=0` the datafit is perfect, but there would be no enforcement |
| 298 | +# of the basis shapes, leading to severe over-fitting. On the other end, as |
| 299 | +# :math:`\mu\to\infty` the reconstruction turns towards the zero matrix, thus |
| 300 | +# completely ignoring the given data. |
| 301 | +# |
| 302 | +# Later publications have tried to mitigate this issue, and have shown that |
| 303 | +# the weighted nuclear norm performs even better when the weights are selected |
| 304 | +# with care [4]_. Other non-convex relaxations show similar results [5]_. |
| 305 | +# |
| 306 | +# **References** |
| 307 | +# |
| 308 | +# .. [1] C. Bregler, A. Hertzmann, and H. Biermann. Recovering non-rigid 3d shape |
| 309 | +# from image streams. In The IEEE Conference on Computer Vision and Pattern |
| 310 | +# Recognition (CVPR), 2000. |
| 311 | +# .. [2] Y. Dai, H. Li, and M. He. A simple prior-free method for non-rigid |
| 312 | +# structure-from-motion factorization. International Journal of Computer Vision, |
| 313 | +# 107(2):101–122, 2014. |
| 314 | +# .. [3] M. Fazel, H. Hindi, and S. P. Boyd. A rank minimization heuristic with |
| 315 | +# application to minimum order system approximation. In the Proceedings of the |
| 316 | +# American Control Conference (ACC), 2001. |
| 317 | +# .. [4] S. Kumar. Non-rigid structure from motion: Prior-free factorization method |
| 318 | +# revisited. In The IEEE Winter Conference on Applications of Computer Vision |
| 319 | +# (WACV), 2020. |
| 320 | +# .. [5] M. Valtonen Örnhag and C. Olsson. A unified optimization framework for |
| 321 | +# low-rank inducing penalties. In the Proceedings of the IEEE/CVF conference |
| 322 | +# on computer vision and pattern recognition (CVPR), 2020. |
| 323 | + |
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