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U3 is defined by
$$U(\theta,\phi,\lambda) = R_z(\phi) R_y(\theta) R_z(\lambda)$$
When $\theta=0$, we get
$$U(0,\phi,\lambda) = R_z(\phi + \lambda)$$
If we restrict to angles in $[0,2\pi)$, then the Clifford operators are
$R_z(0)=I$, $R_z(\pi)=Z$, $R_z(\pi/2)=S$ $R_z(3\pi/2)=S^\dagger$.
Hence as long as $\phi + \lambda$ is a multiple of $\pi/2$ then we have
a Clifford, this PR ensures that this is the case by fixing the lookup
table and adding tests.
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Co-authored-by: Casey Duckering <[email protected]>
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