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Add JAX implementation to ifp_advanced lecture
- Renamed "Implementation" section to "Numba Implementation" - Added new "JAX Implementation" section before "Exercises" - Implemented IFP_JAX as NamedTuple for JAX JIT compatibility - Created global utility functions (u_prime, u_prime_inv, R, Y) - Added create_ifp_jax() factory function - Implemented K_jax Coleman-Reffett operator with JAX - Added solve_model_time_iter_jax solver - Included comparison section showing Numba vs JAX solutions - Configured JAX for 64-bit precision - Fixed import conflicts between numba.jit and jax.jit 🤖 Generated with [Claude Code](https://claude.com/claude-code) Co-Authored-By: Claude <[email protected]>
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lectures/ifp_advanced.md

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@@ -333,7 +333,7 @@ is just $\mathbb E R_t$.
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We test the condition $\beta \mathbb E R_t < 1$ in the code below.
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## Implementation
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## Numba Implementation
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We will assume that $R_t = \exp(a_r \zeta_t + b_r)$ where $a_r, b_r$
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are constants and $\{ \zeta_t\}$ is IID standard normal.
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We can see from the figure that the dynamics will be stable --- assets do not
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diverge even in the highest state.
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## JAX Implementation
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We now provide a JAX implementation of the model.
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JAX is a high-performance numerical computing library that provides automatic differentiation and JIT compilation, with support for GPU/TPU acceleration.
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First we need to import JAX and related libraries:
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```{code-cell} ipython
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import jax
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import jax.numpy as jnp
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from jax import vmap
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from typing import NamedTuple
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# Import jax.jit with a different name to avoid conflict with numba.jit
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jax_jit = jax.jit
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```
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We enable 64-bit precision in JAX to ensure accurate results that match the Numba implementation:
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```{code-cell} ipython
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jax.config.update("jax_enable_x64", True)
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```
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Here's the JAX version of the IFP class using NamedTuple for compatibility with JAX's JIT compilation:
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```{code-cell} ipython
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class IFP_JAX(NamedTuple):
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"""
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A NamedTuple that stores primitives for the income fluctuation
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problem, using JAX.
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"""
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γ: float
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β: float
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P: jnp.ndarray
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a_r: float
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b_r: float
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a_y: float
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b_y: float
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s_grid: jnp.ndarray
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η_draws: jnp.ndarray
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ζ_draws: jnp.ndarray
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def create_ifp_jax(γ=1.5,
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β=0.96,
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P=np.array([(0.9, 0.1),
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(0.1, 0.9)]),
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a_r=0.1,
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b_r=0.0,
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a_y=0.2,
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b_y=0.5,
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shock_draw_size=50,
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grid_max=10,
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grid_size=100,
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seed=1234):
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"""
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Create an instance of IFP_JAX with the given parameters.
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"""
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# Test stability assuming {R_t} is IID and adopts the lognormal
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# specification given below. The test is then β E R_t < 1.
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ER = np.exp(b_r + a_r**2 / 2)
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assert β * ER < 1, "Stability condition failed."
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# Convert to JAX arrays
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P_jax = jnp.array(P)
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# Generate random draws using JAX
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key = jax.random.PRNGKey(seed)
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key, subkey1, subkey2 = jax.random.split(key, 3)
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η_draws = jax.random.normal(subkey1, (shock_draw_size,))
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ζ_draws = jax.random.normal(subkey2, (shock_draw_size,))
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s_grid = jnp.linspace(0, grid_max, grid_size)
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return IFP_JAX(γ=γ, β=β, P=P_jax, a_r=a_r, b_r=b_r, a_y=a_y, b_y=b_y,
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s_grid=s_grid, η_draws=η_draws, ζ_draws=ζ_draws)
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# Utility functions for the IFP model
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def u_prime(c, γ):
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"""Marginal utility"""
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return c**(-γ)
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def u_prime_inv(c, γ):
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"""Inverse of marginal utility"""
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return c**(-1/γ)
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def R(z, ζ, a_r, b_r):
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"""Gross return on assets"""
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return jnp.exp(a_r * ζ + b_r)
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def Y(z, η, a_y, b_y):
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"""Labor income"""
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return jnp.exp(a_y * η + (z * b_y))
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```
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Here's the Coleman-Reffett operator using JAX:
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```{code-cell} ipython
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@jax_jit
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def K_jax(a_in, σ_in, ifp):
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"""
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The Coleman--Reffett operator for the income fluctuation problem,
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using the endogenous grid method with JAX.
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* ifp is an instance of IFP_JAX
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* a_in[i, z] is an asset grid
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* σ_in[i, z] is consumption at a_in[i, z]
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"""
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# Extract parameters from ifp
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γ, β, P = ifp.γ, ifp.β, ifp.P
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a_r, b_r, a_y, b_y = ifp.a_r, ifp.b_r, ifp.a_y, ifp.b_y
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s_grid, η_draws, ζ_draws = ifp.s_grid, ifp.η_draws, ifp.ζ_draws
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n = len(P)
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# Allocate memory
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σ_out = jnp.empty_like(σ_in)
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# Obtain c_i at each s_i, z, store in σ_out[i, z], computing
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# the expectation term by Monte Carlo
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def compute_expectation(s, z):
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"""Compute expectation for given s and z"""
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def inner_expectation(z_hat):
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# Vectorize over shocks
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def compute_term(η, ζ):
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R_hat = R(z_hat, ζ, a_r, b_r)
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Y_hat = Y(z_hat, η, a_y, b_y)
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a_val = R_hat * s + Y_hat
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# Interpolate consumption
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c_interp = jnp.interp(a_val, a_in[:, z_hat], σ_in[:, z_hat])
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U = u_prime(c_interp, γ)
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return R_hat * U
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# Vectorize over all shock combinations
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η_grid, ζ_grid = jnp.meshgrid(η_draws, ζ_draws, indexing='ij')
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terms = vmap(vmap(compute_term))(η_grid, ζ_grid)
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return P[z, z_hat] * jnp.mean(terms)
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# Sum over z_hat states
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Ez = jnp.sum(vmap(inner_expectation)(jnp.arange(n)))
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return u_prime_inv(β * Ez, γ)
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# Vectorize over s_grid and z
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σ_out = vmap(vmap(compute_expectation, in_axes=(None, 0)),
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in_axes=(0, None))(s_grid, jnp.arange(n))
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# Calculate endogenous asset grid
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a_out = s_grid[:, None] + σ_out
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# Fixing a consumption-asset pair at (0, 0) improves interpolation
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σ_out = σ_out.at[0, :].set(0)
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a_out = a_out.at[0, :].set(0)
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return a_out, σ_out
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```
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The next function solves for an approximation of the optimal consumption policy via time iteration using JAX:
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```{code-cell} ipython
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def solve_model_time_iter_jax(model, # Class with model information
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a_vec, # Initial condition for assets
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σ_vec, # Initial condition for consumption
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tol=1e-4,
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max_iter=1000,
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verbose=True,
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print_skip=25):
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# Set up loop
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i = 0
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error = tol + 1
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while i < max_iter and error > tol:
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a_new, σ_new = K_jax(a_vec, σ_vec, model)
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error = jnp.max(jnp.abs(σ_vec - σ_new))
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i += 1
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if verbose and i % print_skip == 0:
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print(f"Error at iteration {i} is {error}.")
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a_vec, σ_vec = a_new, σ_new
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if error > tol:
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print("Failed to converge!")
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elif verbose:
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print(f"\nConverged in {i} iterations.")
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return a_new, σ_new
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```
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Now we can create an instance and solve the model using JAX:
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```{code-cell} ipython
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ifp_jax = create_ifp_jax()
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```
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Set up the initial condition:
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```{code-cell} ipython
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# Initial guess of σ = consume all assets
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k = len(ifp_jax.s_grid)
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n = len(ifp_jax.P)
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σ_init_jax = jnp.empty((k, n))
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for z in range(n):
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σ_init_jax = σ_init_jax.at[:, z].set(ifp_jax.s_grid)
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a_init_jax = σ_init_jax.copy()
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```
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Let's generate an approximation solution with JAX:
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```{code-cell} ipython
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a_star_jax, σ_star_jax = solve_model_time_iter_jax(ifp_jax, a_init_jax, σ_init_jax, print_skip=5)
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```
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Here's a plot comparing the JAX solution with the Numba solution:
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```{code-cell} ipython
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fig, ax = plt.subplots()
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for z in range(len(ifp_jax.P)):
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ax.plot(np.array(a_star_jax[:, z]), np.array(σ_star_jax[:, z]),
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label=f"JAX: consumption when $z={z}$", linestyle='--')
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ax.plot(a_star[:, z], σ_star[:, z],
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label=f"Numba: consumption when $z={z}$", linestyle='-', alpha=0.6)
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plt.legend()
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plt.show()
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```
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### Comparison of Numba and JAX Solutions
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Now let's verify that both implementations produce nearly identical results.
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With 64-bit precision enabled in JAX, we expect the solutions to be very close.
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Let's compute the maximum absolute differences:
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```{code-cell} ipython
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# Convert JAX arrays to NumPy for comparison
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a_star_jax_np = np.array(a_star_jax)
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σ_star_jax_np = np.array(σ_star_jax)
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# Compute differences
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a_diff = np.abs(a_star - a_star_jax_np)
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σ_diff = np.abs(σ_star - σ_star_jax_np)
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print("Comparison of Numba and JAX solutions:")
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print("=" * 50)
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print(f"Max absolute difference in asset grid: {np.max(a_diff):.3e}")
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print(f"Mean absolute difference in asset grid: {np.mean(a_diff):.3e}")
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print(f"Max absolute difference in consumption: {np.max(σ_diff):.3e}")
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print(f"Mean absolute difference in consumption: {np.mean(σ_diff):.3e}")
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```
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Let's also visualize the differences:
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```{code-cell} ipython
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fig, axes = plt.subplots(1, 2, figsize=(12, 4))
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for z in range(len(ifp.P)):
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axes[0].plot(a_star[:, z], a_diff[:, z], label=f'z={z}')
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axes[1].plot(a_star[:, z], σ_diff[:, z], label=f'z={z}')
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axes[0].set_xlabel('assets')
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axes[0].set_ylabel('absolute difference')
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axes[0].set_title('Asset Grid Differences: |Numba - JAX|')
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axes[0].legend()
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axes[1].set_xlabel('assets')
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axes[1].set_ylabel('absolute difference')
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axes[1].set_title('Consumption Differences: |Numba - JAX|')
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axes[1].legend()
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plt.tight_layout()
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plt.show()
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```
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As we can see, the differences between the two implementations are extremely small (on the order of machine precision), confirming that both methods produce essentially identical results.
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The tiny differences arise from:
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- Different random number generators (NumPy vs JAX)
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- Minor differences in floating-point operations order
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- Different interpolation implementations
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Despite these minor numerical differences, both implementations converge to the same optimal policy.
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The JAX implementation provides several advantages:
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1. **GPU/TPU acceleration**: JAX can automatically utilize GPU/TPU hardware for faster computation
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2. **Automatic differentiation**: JAX provides automatic differentiation, which can be useful for sensitivity analysis
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3. **Functional programming**: JAX encourages a functional style that can be easier to reason about and parallelize
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## Exercises
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```{exercise}

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