private vars in Scala do not start with underscore

Author: samuelgruetter

language-adaptors/rxjava-scala/src/main/scala/rx/lang/scala/subscriptions/SerialSubscription.scala

@@ -29,17 +29,17 @@ object SerialSubscription {
 class SerialSubscription private[scala] (val asJavaSubscription: rx.subscriptions.SerialSubscription)
   extends Subscription {
 
-  private val _isUnsubscribed = new AtomicBoolean(false)
+  private val unsubscribed = new AtomicBoolean(false)
 
   /**
    * Checks whether the subscription has been unsubscribed.
    */
-  def isUnsubscribed: Boolean = _isUnsubscribed.get()
+  def isUnsubscribed: Boolean = unsubscribed.get()
 
   /**
    * Unsubscribes this subscription, setting isUnsubscribed to true.
    */
-  override def unsubscribe(): Unit = { super.unsubscribe(); _isUnsubscribed.set(true) }
+  override def unsubscribe(): Unit = { super.unsubscribe(); unsubscribed.set(true) }
 
   def subscription_=(value: Subscription): Unit = asJavaSubscription.setSubscription(value.asJavaSubscription)
   def subscription: Subscription = Subscription(asJavaSubscription.getSubscription)

language-adaptors/rxjava-scala/src/main/scala/rx/lang/scala/subscriptions/Subscription.scala

@@ -65,11 +65,11 @@ object Subscription {
   def apply(u: => Unit): Subscription  = {
     new Subscription () {
 
-      private val _isUnsubscribed = new AtomicBoolean(false)
-      def isUnsubscribed = _isUnsubscribed.get()
+      private val unsubscribed = new AtomicBoolean(false)
+      def isUnsubscribed = unsubscribed.get()
 
       val asJavaSubscription = new rx.Subscription {
-        def unsubscribe() { u; _isUnsubscribed.set(true) }
+        def unsubscribe() { u; unsubscribed.set(true) }
       }
     }
   }