Create operator to remove undefined props

[renatodysouza]

It is easy to resolve, but if this operator could exist.

Example
const myFormValue = {
name: 'John',
age: '',
city: ''
};

of(myFormValue ).pipe(removeUndefinedProps).subscribe(val => console.log(val)); // { name: john }

[josepot]

It's probably easier to define a mapper function like removeFalsyProps and then use it with map:

const removeFalsyProps = (obj) => Object.fromEntries(
  Object.entries(obj).filter(([, val]) => val)
);

of(myFormValue).pipe(
  map(removeFalsyProps)
)

[renatodysouza]

Hi Josepot, Everthing ok, I hope so. I agree with with you, but the idea is put this feature built-in . Normal all feature are easy, the question is resolve not the imperative way, but declarative way.

Best regards,