✅ How to parse form-data as input?

[james10424]

How to parse form-data with zod types as input? By default it doesn't seem to parse it unless I have at least one ez.upload() in the input field. I worked around it by doing this:

input: z.object({
  key: z.string(),
  a: ez.upload().optional(),
})

Is there a more elegant way of doing this?

[RobinTail]

@james10424 , starting v22.12.0 you can use ez.form() instead of (or wrapping) z.object():

import { defaultEndpointsFactory, ez } from "express-zod-api";
import { z } from "zod";

export const submitFeedbackEndpoint = defaultEndpointsFactory.build({
  method: "post",
  input: ez.form({
    name: z.string().min(1),
    email: z.string().email(),
    message: z.string().min(1),
  }),
});

More details: https://github.com/RobinTail/express-zod-api/blob/master/README.md#html-forms-url-encoded

[james10424]

Awesome, thank you for taking a look!