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加入 较少参数，存在性能收益可能性 的解释 原因如下 1,rust编译的 硬件指令对于较少函数参数会优先使用寄存器（大部分如此） 2,ffi 类型的函数，有明确规范定义
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感谢贡献 |
ZhangHanDong
merged commit 63c6e8a
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Rust-Coding-Guidelines:main
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加入 较少参数，存在性能收益可能性 的解释
原因如下
1,rust编译的 硬件指令对于较少函数参数会优先使用寄存器（大部分如此）
2,ffi 类型的函数，有明确规范定义