leds: multicolor: Use rounded division when calculating color components

Given channel intensity, LED brightness and max LED brightness, the
multicolor LED framework helper led_mc_calc_color_components() computes
the color channel brightness as

    chan_brightness = brightness * chan_intensity / max_brightness

Consider the situation when (brightness, intensity, max_brightness) is
for example (16, 15, 255), then chan_brightness is computed to 0
although the fractional divison would give 0.94, which should be rounded
to 1.

Use DIV_ROUND_CLOSEST here for the division to give more realistic
component computation:

    chan_brightness = DIV_ROUND_CLOSEST(brightness * chan_intensity,
                                        max_brightness)

Fixes: 55d5d3b ("leds: multicolor: Introduce a multicolor class definition")
Signed-off-by: Marek Behún <[email protected]>
Link: https://lore.kernel.org/r/[email protected]
Signed-off-by: Lee Jones <[email protected]>

Author: elkablo

drivers/leds/led-class-multicolor.c

@@ -6,6 +6,7 @@
 #include <linux/device.h>
 #include <linux/init.h>
 #include <linux/led-class-multicolor.h>
+#include <linux/math.h>
 #include <linux/module.h>
 #include <linux/slab.h>
 #include <linux/uaccess.h>
@@ -19,9 +20,10 @@ int led_mc_calc_color_components(struct led_classdev_mc *mcled_cdev,
 	int i;
 
 	for (i = 0; i < mcled_cdev->num_colors; i++)
-		mcled_cdev->subled_info[i].brightness = brightness *
-					mcled_cdev->subled_info[i].intensity /
-					led_cdev->max_brightness;
+		mcled_cdev->subled_info[i].brightness =
+			DIV_ROUND_CLOSEST(brightness *
+					  mcled_cdev->subled_info[i].intensity,
+					  led_cdev->max_brightness);
 
 	return 0;
 }