perf dwarf-aux: Print array type name with "[]"

It's confusing both pointers and arrays are printed as *.  Let's print
array types with [] so that we can identify them easily.  Although it's
interchangable, sometimes it can cause confusion with size like in the
below example.

Note that it is not the same with C syntax where it goes to the variable
names, but we want to have it in the type names (like in Go language).

Before:
  mov [20] 0x68(reg5) -> reg0 type='struct page**' size=0x80 (die:0x4e61d32)

After:
  mov [20] 0x68(reg5) -> reg0 type='struct page*[]' size=0x80 (die:0x4e61d32)

Signed-off-by: Namhyung Kim <[email protected]>
Acked-by: Masami Hiramatsu <[email protected]>
Cc: Adrian Hunter <[email protected]>
Cc: Ian Rogers <[email protected]>
Cc: Ingo Molnar <[email protected]>
Cc: Jiri Olsa <[email protected]>
Cc: Kan Liang <[email protected]>
Cc: Peter Zijlstra <[email protected]>
Link: https://lore.kernel.org/r/[email protected]
Signed-off-by: Arnaldo Carvalho de Melo <[email protected]>

Author: namhyung

tools/perf/util/dwarf-aux.c

@@ -1110,8 +1110,10 @@ int die_get_typename_from_type(Dwarf_Die *type_die, struct strbuf *buf)
 	const char *tmp = "";
 
 	tag = dwarf_tag(type_die);
-	if (tag == DW_TAG_array_type || tag == DW_TAG_pointer_type)
+	if (tag == DW_TAG_pointer_type)
 		tmp = "*";
+	else if (tag == DW_TAG_array_type)
+		tmp = "[]";
 	else if (tag == DW_TAG_subroutine_type) {
 		/* Function pointer */
 		return strbuf_add(buf, "(function_type)", 15);