Fixes examples in README.md

Author: kzaher

README.md

@@ -26,15 +26,15 @@ Writing table and collection view data sources is tedious. There is a large numb
 RxSwift helps alleviate some of the burden with a simple data binding mechanism:
 1) Turn your data into an Observable sequence
 2) Bind the data to the tableView/collectionView using one of:
-  - `rx_items(dataSource:protocol<RxTableViewDataSourceType, UITableViewDataSource>)`
-  - `rx_items(cellIdentifier:String)`
-  - `rx_items(cellIdentifier:String:Cell.Type:_:)`
-  - `rx_items(_:_:)`
+  - `rx.items(dataSource:protocol<RxTableViewDataSourceType, UITableViewDataSource>)`
+  - `rx.items(cellIdentifier:String)`
+  - `rx.items(cellIdentifier:String:Cell.Type:_:)`
+  - `rx.items(_:_:)`
 
 ```swift
-let dataSource = Observable<[String]>.just(["first element", "second element", "third element"])
+let data = Observable<[String]>.just(["first element", "second element", "third element"])
 
-dataSource.bindTo(tableView.rx.items(cellIdentifier: "Cell")) { index, model, cell in
+data.bindTo(tableView.rx.items(cellIdentifier: "Cell")) { index, model, cell in
   cell.textLabel?.text = model
 }
 .addDisposableTo(disposeBag)
@@ -47,7 +47,8 @@ These are precisely the use cases that RxDataSources helps solve.
 With RxDataSources, it is super easy to just write
 
 ```swift
-Observable.just([MySection(header: "title", items: [1, 2, 3])])
+let dataSource = RxTableViewSectionedReloadDataSource<SectionModel<String, Int>>()
+Observable.just([SectionModel(model: "title", items: [1, 2, 3])])
     .bindTo(tableView.rx.items(dataSource: dataSource))
     .addDisposableTo(disposeBag)
 ```
@@ -95,7 +96,7 @@ let dataSource = RxTableViewSectionedReloadDataSource<SectionOfCustomData>()
 
 ```swift 
 dataSource.configureCell = { ds, tv, ip, item in
-  let cell = tv.dequeueReusableCellWithIdentifier("Cell", forIndexPath: ip)
+  let cell = tv.dequeueReusableCell(withIdentifier: "Cell", for: ip)
   cell.textLabel?.text = "Item \(item.anInt): \(item.aString) - \(item.aCGPoint.x):\(item.aCGPoint.y)"
   return cell
 }