Update LaTeXify ref tests

Author: YingboMa

test/latexify/10.tex

@@ -1,5 +1,5 @@
 \begin{align}
-\frac{\mathrm{d} x\left( t \right)}{\mathrm{d}t} =& \frac{\sigma \left(  - x\left( t \right) + y\left( t \right) \right) \frac{\mathrm{d}}{\mathrm{d}t} \left(  - y\left( t \right) + x\left( t \right) \right)}{\frac{\mathrm{d} z\left( t \right)}{\mathrm{d}t}} \\
-0 =&  - y\left( t \right) + \frac{1}{10} \sigma \left( \rho - z\left( t \right) \right) x\left( t \right) \\
-\frac{\mathrm{d} z\left( t \right)}{\mathrm{d}t} =& \left( y\left( t \right) \right)^{\frac{2}{3}} x\left( t \right) - \beta z\left( t \right)
+\frac{\mathrm{d} x\left( t \right)}{\mathrm{d}t} =& \frac{\left(  - x\left( t \right) + y\left( t \right) \right) \frac{\mathrm{d}}{\mathrm{d}t} \left( x\left( t \right) - y\left( t \right) \right) \sigma}{\frac{\mathrm{d} z\left( t \right)}{\mathrm{d}t}} \\
+0 =&  - y\left( t \right) + \frac{1}{10} x\left( t \right) \left(  - z\left( t \right) + \rho \right) \sigma \\
+\frac{\mathrm{d} z\left( t \right)}{\mathrm{d}t} =& \left( y\left( t \right) \right)^{\frac{2}{3}} x\left( t \right) - z\left( t \right) \beta
 \end{align}

test/latexify/20.tex

@@ -1,5 +1,5 @@
 \begin{align}
-\frac{\mathrm{d}}{\mathrm{d}t} u(t)_1 =& \left(  - u(t)_1 + u(t)_2 \right) p_3 \\
-0 =&  - u(t)_2 + \frac{1}{10} \left(  - u(t)_1 + p_1 \right) p_2 p_3 u(t)_1 \\
+\frac{\mathrm{d}}{\mathrm{d}t} u(t)_1 =& p_3 \left(  - u(t)_1 + u(t)_2 \right) \\
+0 =&  - u(t)_2 + \frac{1}{10} \left( p_1 - u(t)_1 \right) p_2 p_3 u(t)_1 \\
 \frac{\mathrm{d}}{\mathrm{d}t} u(t)_3 =& u(t)_2^{\frac{2}{3}} u(t)_1 - p_3 u(t)_3
 \end{align}

test/latexify/30.tex

@@ -1,5 +1,5 @@
 \begin{align}
-\frac{\mathrm{d}}{\mathrm{d}t} u(t)_1 =& \left(  - u(t)_1 + u(t)_2 \right) p_3 \\
-\frac{\mathrm{d}}{\mathrm{d}t} u(t)_2 =&  - u(t)_2 + \frac{1}{10} \left(  - u(t)_1 + p_1 \right) p_2 p_3 u(t)_1 \\
+\frac{\mathrm{d}}{\mathrm{d}t} u(t)_1 =& p_3 \left(  - u(t)_1 + u(t)_2 \right) \\
+\frac{\mathrm{d}}{\mathrm{d}t} u(t)_2 =&  - u(t)_2 + \frac{1}{10} \left( p_1 - u(t)_1 \right) p_2 p_3 u(t)_1 \\
 \frac{\mathrm{d}}{\mathrm{d}t} u(t)_3 =& u(t)_2^{\frac{2}{3}} u(t)_1 - p_3 u(t)_3
 \end{align}