Codesnippet - check inactive user from List and apply field style (#1701)

* Apply Field Style on List type field based on condition

If one of the reviewers is inactive, highlight the corresponding column in list view.

* Apply Field Style on Reviewers if anyone is inactive

* Check inactive user in the List type field and apply Style

* Apply Field Style on Reviewers if anyone is inactive

Author: GHSayak25

Server-Side Components/Server Side/MarkInactiveUsersonList/README.md

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+There is a list type field named 'Reviewers' on Policy records.
+On the list view of Policies, we want to highlight with field styles, where any of the user listed under Reviewers is inactive.
+In the screenshot attached below, Daniel Zill is inactive user, and if he is present in Reviewers, the respective column value is applied with defined field styles.
+<img width="809" height="370" alt="image" src="https://github.com/user-attachments/assets/b483207e-f3ba-4db7-a717-d392694eaf50" />
+<img width="433" height="107" alt="image" src="https://github.com/user-attachments/assets/5129038f-d210-40f4-bcd8-1727d791edca" />
+
+The condition to check if any inactive user is present in Reviewers must be written on 'Value' (actual Server script) and the styles to applied must be mentioned on 'Style'.
+Refer below screenshot:
+<img width="911" height="239" alt="image" src="https://github.com/user-attachments/assets/477e52cb-bdad-439d-a1cc-5b6be0415c20" />
+

Server-Side Components/Server Side/MarkInactiveUsersonList/fieldStyleforListfields.js

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+//The below code followed by "javascript:", inside 'Value' field for the List type Reviewers field's Style record will do the condition check.
+var answer = false;
+var arr=[];
+arr = current.reviewers.split(',');
+for(i=0; i<arr.length; i++){
+  var gr = new GlideRecord('sys_user');
+  gr.addQuery('sys_id',arr[i]);
+  gr.query();
+  if(gr.next()){
+    if(gr.active == false){
+      answer = true;
+    }
+  }
+}
+answer;
+
+//The Style field then must be populated with the style we want to apply. I have applied "background-color: blue;" "text-decoration:line-through;"
+background-color: blue;
+text-decoration:line-through;